## Textile Calculations, Manufacture and Mechanism |

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### Common terms and phrases

allowing angle antilog base Bradford calculate centre change wheel circle circumference cloth constant coordinate corresponding cost cotton counts cubic curve cylinder diameter distance Divide Draft drams draw driving ends per inch equal equation equivalent EXAMPLE feet figure finished front give given grains graph hanks Hence increase length logarithms loom marked material means measured method moves Multiply notice number of ends Number of teeth obtain picks per inch piece position proportional pulley quantity radius ratio repeat represent result revolutions per minute right angle roller Scale shaft sides silk Speed splits square straight line student Suppose teeth threads triangle twist units varies volume warp warp threads weave weft weigh 1 lb weight wheel width wool woollen worsted yards weigh yarn Yorkshire skeins

### Popular passages

Page 113 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz.

Page 414 - F. 1 Knot = 6080 feet per hour. Weight of 1 Ib. in London = 445,000 dynes. One pound avoirdupois = 7000 grains = 453'6 grammes. 1 Cubic foot of water weighs 62-3 Ibs. at 65° F. 1 Cubic foot of air at 0

Page 79 - Suppose that a*=n, then x is called the logarithm of n to the base a : thus the logarithm of a number to a given base is the index of the power to which the base must be raised to be equal to the number. The logarithm of n to the base a is written log.

Page 82 - The logarithm of the root of a number is found by dividing the logarithm of the number by the index of the root.

Page 121 - Guido, with a burnt stick in his hand, demonstrating on the smooth paving-stones of the path, that the square on the hypotenuse of a right-angled triangle is equal to the sum of the squares on the other two sides.

Page 414 - Ib. per square foot = 760 mm. of mercury = 10" dynes per sq. cm. nearly. A column of water 2-3 feet high corresponds to a pressure of 1 Ib. per sq.

Page 206 - Put another way, if you construct squares on the edges of a right-angled triangle, the area of the square on the hypotenuse is equal to the sum of the areas of the squares on the other two sides.