 | Bourdon (M., Louis Pierre Marie) - Algebra - 1831 - 326 pages
...left of the divisor, and the first term of the quotient is found ; multiply the divisor by this term, and subtract the product from the dividend. Divide the first term of this remainder by the first term of the divisor, and the second term of the quotient is found ; multiply... | |
 | Ebenezer Bailey - Algebra - 1835 - 258 pages
...first tern of the divisor, for the first term of the quotient. Multiply the whole divisor by this term, and subtract the product from the dividend. Divide the first term of the remainder by the Jirst term of the divisor, for the second term of the quotient. Multiply the whole divisor by... | |
 | Ormsby MacKnight Mitchel - Algebra - 1845 - 308 pages
...term of the divisor, and place the quotient in the quotient, as its first term. Multiply every term of the divisor by the first term of the quotient, and subtract the product from the dividend, and oring down the remainder. Divide the first term of the remainder by the first term of the divisor,... | |
 | Stephen Chase - Algebra - 1849 - 348 pages
...and set the result, with its proper sign, as a term of the quotient. '3. Multiply the divisor by this first term of the quotient, and subtract the. product from the. dividend, 4. Divide the first term of the remainder by the first term of the divisor, set the result in the quotient... | |
 | William Smyth - Algebra - 1851 - 272 pages
...result, with its proper sign, as the first term of the quotient. 2°. Multiply the divisor by this first term of the quotient and subtract the product from the dividend. 3°. Divide the first term of the remainder by the first term of the divisor, place the result in the... | |
 | Joseph Ray - Algebra - 1852 - 408 pages
...the divisor ; the result will be the first term of the quotient. Multiply the divisor by this term, and subtract the product from the dividend. Divide the first term of the remainder by the first term of the divisor; the result will be the second term of the quotient. Multiply the... | |
 | Joseph Ray - Algebra - 1848 - 250 pages
...the divisor, the result will be the first term of the quotient. Multiply the dicisor by this term, and subtract the product from the dividend Divide the first term of the remainder by the first term oftlie divisor, the result will be the second term of the quotient. Multiply the... | |
 | John Robertson (LL.D., of Upton Park sch.) - 1861 - 140 pages
...the dividend by that of the divisor, and set the result in the quotient ; (iii.) Multiply the whole divisor by the first term of the quotient, and subtract the product from the dividend ; (iv.) Bring down fresh terms (as may be required) from the dividend, and repeat the whole operation.... | |
 | Joseph Ray - Algebra - 1852 - 422 pages
...the divisor ; the result will be the first term of the quotient. Multiply the divisor ty this term, and subtract the product from the dividend. Divide the first term of the remainder by the first term of the divisor; the result will be the second term of the quotient. Multiply the... | |
 | Robert Wallace - 1870 - 164 pages
...term on the left of the divisor for the first term of the quotient. Multiply the whole divisor by this term of the quotient, and subtract the product from...the dividend. Divide the first term of the remainder by the first term of the divisor for a second term of the quotient ; multiply as before, and subtract... | |
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Divide the first term of the dividend by the first term of the divisor, and write the result as the first term of the quotient. 
