The Elements of Analytical Geometry ...
Carey, Lea & Blanchard, 1835 - Geometry, Analytic - 288 pages
What people are saying - Write a review
We haven't found any reviews in the usual places.
Other editions - View all
Common terms and phrases
abscissa assumed asymptotes axes axis base becomes bisects called centre chords circle coefficients conjugate consequently constant construction containing coordinates curve denote described determine diameter difference distance divided draw drawn ellipse equa equal equation expression extremities focus follows former Geom geometrical given point gives greater half hence hyperbola inclination inscribed intersection join known length less locus manner meet negative oblique obtain obviously ordinate origin parabola parallel passing perpendicular plane point of contact positive preceding principal diameters PROBLEM projections proposed radius rectangle rectangular reduces referred remaining represent respectively right angle shows sides sought square straight line substituting suppose surface tangent tion transformed triangle vertex vertical whence
Page 31 - To find the side of an equilateral triangle inscribed in a circle, multiply the diameter of the circle by .866.
Page 30 - Having given the side of a regular decagon inscribed in a circle whose radius is known, to find the side of a regular pentagon inscribed in the same circle.
Page 200 - Given the base and the sum of the sides of a triangle, to find the locus of the point of intersection of lines from the angles bisecting the opposite sides.
Page 109 - They may cut each other, having two points common, when the distance between the centers is less than the sum and greater than the difference of the radii.
Page 153 - ... does. From the general expression for the subtangent, just given, it follows that that is, as in the ellipse, the rectangle of the subtangent and abscissa of the point of contact is equal to the rectangle of the sum and difference of the same abscissa and semi-transverse axis. Thus OM-MR = A'M-MB...
Page 196 - Given the base of a triangle and the difference of the angles at the base, to determine the locus of the vertex. Taking the same axes as before, and putting a, a', for the tangents of the angles at the base...
Page 37 - In an oblique-angled plane triangle ; there is given the difference of the sides which includes the angle of 71° 10,' equal to 11, and the line that bisects the said angle is equal to 24 ; from whence is required a theorem that will determine the base and sides of the said triangle. The figure can be supplied by the reader.
Page 67 - In a triangle, having given the ratio of the two* sides, together with both the segments of the base, made by a perpendicular from the vertical angle, to determine the sides of the triangle.
Page 104 - ... y", and there results for the tangent the equation y — y' = ; (x — a/), as before found. which is obviously that of a perpendicular to this, through the point (a/, y',) that the tangent through any point is perpendicular to the radius at that point, a property which was assumed in the preceding investigation. PROBLEM II. (26.) To draw a tangent to a circle from a given point without it. Let (a...
Page 37 - In an isosceles triangle, the square of a line drawn from the vertex to any point in the base, together with the rectangle of the segments of the base, is equal to the square of one of the equal sides of the triangle.