 | Euclid, John Bascombe Lock - Euclid's Elements - 1892 - 188 pages
...To bitect is to divide into two equal parts. 5. Use the construction of Question 2 to shew that when two sides of a triangle are equal, the angles opposite those sides are also equal. 6. AB, BC, CD are three straight lines such that AB=CD and the angle .4.8(7= the angle... | |
 | Wooster Woodruff Beman, David Eugene Smith - Geometry - 1895 - 346 pages
...determine the remaining par,ts. 35. State the reciprocal of ex. 34 and tell whether it is true, and why. Theorem 3. If two sides of a triangle are equal, the...the figure. Then suppose m to bisect Z ba. 2. Then -.' a=b, Given 3. and Z bm = Z ma, AMB 4. and m= m, 5. .'. AAMC^ABMC, Th. 1 (State th. 1.) 6. and ZA... | |
 | Wooster Woodruff Beman, David Eugene Smith - Geometry, Modern - 1899 - 272 pages
...sides and the included angle of a triangle determine the remaining parts. PROPOSITION III. 66. Theorem. If two sides of a triangle are equal, the angles opposite those sides are equal. Given the A AB C with AC = B C. To prove that Z A = Z B. Proof. 1. Suppose m to bisect Z. ba. 2. Then v6 = a, 3.... | |
 | Wooster Woodruff Beman, David Eugene Smith - Geometry - 1899 - 400 pages
...sides and the included angle of a triangle determine the remaining parts. PROPOSITION III. 66. Theorem. If two sides of a triangle are equal, the angles opposite those sides are equal. Given the A AB C with AC = B C. To prove that Z A = Z B. Proof. 1. Suppose m to bisect Z.ba. 2. Then vi = a, Given... | |
 | Wooster Woodruff Beman, David Eugene Smith - Geometry, Modern - 1899 - 265 pages
...sides and the included angle of a triangle determine the remaining parts. PROPOSITION III. 66. Theorem. If two sides of a triangle are equal, the angles opposite those sides are equal. MB Given the A ABC with AC = B C. To prove that ZA=ZB. Proof. 1. Suppose m to bisect Z ba. 2. Then... | |
 | Thomas Franklin Holgate - Geometry - 1901 - 462 pages
...is one, and only one, ' point of bisection ' or ' mid-point ' of a line. segment. PROPOSITION VI 48. If two sides of a triangle are equal, the angles opposite those sides are also equal. A Let ABC be an isosceles triangle, BA and CA being the equal sides. It is required to... | |
 | Thomas Franklin Holgate - Geometry - 1901 - 462 pages
...one, and only one, ' point of bisection ' or ' mid-point ' of a linesegment. PROPOSITION VI 48. // two sides of a triangle are equal, the angles opposite those sides are also equal. A Let ABC be an isosceles triangle, BA and CA being the equal sides. It is required to... | |
 | Eugene Randolph Smith - Geometry, Plane - 1909 - 204 pages
...a point within, the angle formed is greater than the angle opposite that side. 100. Theorem IV. // two sides of a triangle are equal, the angles opposite those sides are equal. An auxiliary line is necessary, but the analysis will show what line is necessary. What method of proving... | |
 | George Clinton Shutts - Geometry - 1912 - 392 pages
...and is opposite side AM. • • ZB = LC, being homologous angles in congruent triangles. Therefore, If two sides of a triangle are equal, the angles opposite those sides are equal. REMARK. Observe that LB is an angle in each of two triangles. In A AMB it lies opposite the side AM,... | |
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... 3. If two sides of a triangle are equal, the angles opposite these sides are equal ; and conversely. 
