New Plane and Solid Geometry |
From inside the book
Results 1-5 of 40
Page 8
... construct an angle equal to a given angle . B E -D K Let it be required to construct with E as the vertex , and ED as a side , an angle equal to angle ABC . With B as a centre , and any radius , describe an arc inter- secting AB at G ...
... construct an angle equal to a given angle . B E -D K Let it be required to construct with E as the vertex , and ED as a side , an angle equal to angle ABC . With B as a centre , and any radius , describe an arc inter- secting AB at G ...
Page 9
... construct the triangle . n m 10 E n A B m Let it be required to construct the triangle having for two of its sides the straight lines m and n , and their included angle equal to angle E. Draw line AB equal to m , and construct angle ...
... construct the triangle . n m 10 E n A B m Let it be required to construct the triangle having for two of its sides the straight lines m and n , and their included angle equal to angle E. Draw line AB equal to m , and construct angle ...
Page 10
Webster Wells. 31. Given the three sides of a triangle , to construct the triangle . n m p A n m B Let it be required to construct the triangle having for its sides the straight lines m , n , and p . Take the straight line AB equal to m ...
Webster Wells. 31. Given the three sides of a triangle , to construct the triangle . n m p A n m B Let it be required to construct the triangle having for its sides the straight lines m , n , and p . Take the straight line AB equal to m ...
Page 14
... construct △ EDG equal to A , the constructed side being DG : on DG take DF equal to AC : draw line FE . We now have : Given , in A ABC and DEF , To Prove AB = DE , AC = DF , and ZA = ZD . △ ABC = △ DEF . Proof . 1. Superpose A ABC ...
... construct △ EDG equal to A , the constructed side being DG : on DG take DF equal to AC : draw line FE . We now have : Given , in A ABC and DEF , To Prove AB = DE , AC = DF , and ZA = ZD . △ ABC = △ DEF . Proof . 1. Superpose A ABC ...
Page 14
... construct △ EDG equal to ZA : at E construct / DEH equal to ≤ B. Let F be point of intersection of DG and EH . We now have : Given , in △ ABC and DEF , To Prove AB = DE , △ A = ≤ D , and ≤B = LE . △ ABC = △ DEF . Proof . 1 ...
... construct △ EDG equal to ZA : at E construct / DEH equal to ≤ B. Let F be point of intersection of DG and EH . We now have : Given , in △ ABC and DEF , To Prove AB = DE , △ A = ≤ D , and ≤B = LE . △ ABC = △ DEF . Proof . 1 ...
Other editions - View all
Common terms and phrases
ABC and A'B'C adjacent angles altitude angle formed angles are equal apothem arc BC base and altitude bisector bisects centre chord circle circumference circumscribed coincide construct Converse of Prop diagonals diameter diedral angle distance Draw line equal parts occur equal respectively equally distant equilateral triangle exterior angle faces frustum Given line given point homologous sides hypotenuse intersecting isosceles trapezoid isosceles triangle LAOB lateral area lateral edges line drawn lines be drawn measured by arc middle point number of sides oblique lines opposite parallel parallelogram parallelopiped perimeter perpendicular plane MN polyedron prism Proof proportional Prove pyramid quadrilateral radii radius rectangle regular polygon rhombus right angles right triangle secant segments slant height spherical polygon spherical triangle square straight line surface tangent tetraedron THEOREM trapezoid triedral vertex vertices volume