 | Steam-engines - 1865 - 580 pages
...LENGTH AND DIAMETER. RULE. — Multiply 2-25 times the length of the pipe in miles by the square of the velocity of the water in the pipe in feet per second, and divide the product ~by the diameter of the pipe in feet. The quotient is the head of water in feet... | |
 | John Bourne - Steam-engines - 1873 - 510 pages
...AND DIAMETEE. RULE. — Multiply 2-25 times the length of tlie pipe in miles by the square of tlie velocity of the water in the pipe in feet per second, and divide the product by the diameter of the pipe in feet. The quotient is the head of water in feet that... | |
 | Walter S. Hutton - 1885 - 486 pages
...the following Rule (Prony's) : Multiply 2-25 times the length of the pipe in miles by the square of the velocity of the water in the pipe in feet per second, ind divide the product by the diameter of the pipe in feet: the result will be head of water in feet... | |
 | Engineering - 1887 - 214 pages
...the pipe for a given demand, the smaller the friction. To obtain this loss from friction, first find the velocity of the water in the pipe in feet per second by dividing the quantity of water passing through the pipe by the area of the pipe, all dimensions... | |
 | Manfred Powis Bale - Pumping machinery - 1892 - 210 pages
...straight pipes (Prony's rule). — Multiply 2-25 times the length of the pipe in miles by the square of the velocity of the water in the pipe in feet per second, and divide the product by the diameter of the pipe in feet ; the result will be the head of water in feet... | |
 | Institution of Civil Engineers (Great Britain) - Civil engineering - 1897 - 460 pages
...pressure/ in pounds per square inch above the static pressure : — / = £ . _ L " 2rm + M T• where » is the velocity of the water in the pipe in feet per second. AWB 27(e Estimation of Oxygen in Coal-Gas. (Journal of Gas Lighting, 17 August, 1897, p. 370.) The... | |
 | Walter S. Hutton - Engineering - 1901 - 552 pages
...this product multiplied by 6-24 gives the number of gallons discharged per minute. by the square of the velocity of the water in the pipe in feet per second, and divide the product by the diameter of the pipe in feet: the result will be head of water in feet required... | |
 | David Allan Low - Mechanics, Applied - 1909 - 574 pages
...the loss of head in the pipe is 0'0003/trvW, I being the length in feet, d the diameter in feet, v the velocity of the water in the pipe in feet per second. [BE] ANSWEES II. pp. 21-23. 1. 66; 3-75; 19; 8-2. 2. 210; 1584; 1824; 2952'H. 3. 22-5; 35; 19; 29'83.... | |
 | Henry Lewis Rietz, Arthur Robert Crathorne - Algebra - 1909 - 292 pages
...the reservoir in feet, d the diameter of the pipe in inches, L the length of the pipe in feet, and v the velocity of the water in the pipe in feet per second, then according to Cox's formula L 1200 Find the velocity of water in a 5-inch pipe, 1000 feet long,... | |
 | Frederick Charles Lea - Hydraulics - 1923 - 622 pages
...2-7 2-7 3-0 3-8 5-7 7-0 HVDRAULICS 4 inches diameter pipes was the same and was equal to *» v being the velocity of the water in the pipe in feet per second. 0 4 4 6 8 10 LJ 14 Rtdiu of Bead in Diameters. Fig. 370. Loss of head due to bends in pipes 3" and... | |
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Multiply 2-25 times the length of the pipe in miles by the square of the velocity of the water in the pipe in feet per second... 
