 | Geography - 1867 - 878 pages
...known, and the height of the perpendicular is required. This, by the before-mentioned Proposition, is equal to the square root of the difference of the squares of the base and hypothennse, or -J 452 — 121 = ^025 — 144 = »'Ï88Ï = 43} feet, approximately. EXAMPLI... | |
 | Isaac Dalby - Mathematics - 1807 - 476 pages
...equal to the radius, then BPG is an arc of 60°. And because the angle SGB is a right one (72), SG is equal to the square root of the difference of the squares of SB and BG i83, coral.-). The square of SB is 4, and the square of BG is 1, therefore SG the supplemental... | |
 | Charles Hutton - Mathematics - 1811 - 404 pages
...therefore, = rci» + *«: and this being = a2, we have ».-- — — kr. But the altitude of the coae is equal to the square root of the difference of the squares of the side and of the radius of the base ; that is, it is = ^/( — ). And this multiplied: into- 4 of the... | |
 | George Fisher (accountant.) - 1811 - 302 pages
...or Breadth of the 16 Ditch. lof 3. If tj!e Height of a Tower or Perpendicular B were required, then the Square Root of the Difference of the Squares of the Hypotenuse and Base is the height of tb« jferpendieular BC, thus: 2500 900 (30 Yards. Number of Mtn being given to... | |
 | Charles Butler - 1814 - 582 pages
...1.) C5)8=BZ>1I' + ^, and C7f)9-BDl»=CD>, ••• CD= vCBl2-"^* i that is, the co-sine of an arc is equal to the square root of the difference of the squares of the radius and line. Secondly. Let CB the radius, and CD the co-sine be given. to find BD the sine; thus,... | |
 | John Bonnycastle - Trigonometry - 1818 - 488 pages
...equal to the square root of the sum of the squares of the other two sides ; and either of the sides is equal to the square root of the difference of the squares of the hypothenuse and the other side. Note, also, that if the half difference of any two quantities be added... | |
 | Michael Walsh - Arithmetic - 1828 - 312 pages
...perpendicular is the length of the base. 13 The base and hypotenuse given, to find the perpendicular, RULE. The square root of the difference of the squares of the hypotenuse and base is the height of the perpendicular. NB The two last questions may be varied for examples to the... | |
 | Michael Walsh - Arithmetic - 1828 - 318 pages
...perpendicular и the length Of the base. The base and hypotenuse given, to find the perpendicular. Rcr.E. Tlie square root of the difference of the squares of the hypotenuse and base is the height of the perpendicular. NB The two last questions may be varied for examples to tlio... | |
 | Arithmetic - 1829 - 196 pages
...ROOT of the suit OF TUB SQUARES of the two shortest sides, is the length of the HYPOTENUSE. RULE 2. The SQUARE ROOT of the DIFFERENCE OF THE SQUARES of the HYPOTENUSE and EITHER of the other sides, is the length of the REMAINING side. Applying the rule to example 18, \/4a... | |
 | Pierce Morton - Geometry - 1830 - 584 pages
...Therefore, &c. Cor. 1. In a right-angled triangle, the square of either of the two sides is equal to the difference of the squares of the hypotenuse and the other side. Cor. 2. It appears, from the demonstration, that if a perpendicular be drawn from the right angle to... | |
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... is equal to the square root of the difference of the squares of the hypotenuse and the other side. 
