If two chords intersect within a circle, the product of the segments of one is equal to the product of the segments of the other. General Mathematics - Page 294by Raleigh Schorling, William David Reeve - 1922Full view - About this book
| 1906 - 628 pages
...and QB tangents of the circle O; prove RQ minus RA plus QB. 3. If two chords in a circle intersect, the product of the segments of one chord is equal to the product of the segments of the other chord. 4. The side of an equilateral triangle is a. Find the area. 5. In a circle whose radius is 50... | |
| Michigan Schoolmasters' Club - Education - 1894 - 554 pages
...study of Boyle's Law. Of this class, is the following: "If two chords be drawn through a fixed point within a circle, the product of the segments of one...equal to the product of the segments of the other." The data could be arranged as follows : ab Pass various lines through P and measure accurately the... | |
| Webster Wells - Geometry - 1894 - 400 pages
...Subtracting (2) from (1), PROPOSITION XXXI. THEOBEM. 280. If any two chords be drawn through a fixed point within a circle, the product of the segments of one...equal to the product of the segments of the other. Let AB and A'B' be any two chords passing through the fixed point P within the circle ABB '. To prove... | |
| Webster Wells - Geometry - 1894 - 394 pages
...— ~BC* = 2ABX DE. PROPOSITION XXXI. THEOREM. 280. If any two chords be drawn through a fixed point within a circle, the product of the segments of one chord is equal to the prod net of the segments of the other. Let AB and A'B' be any two chords passing through the fixed... | |
| George D. Pettee - Geometry, Plane - 1896 - 272 pages
...product of any other and its external segment. Dem. AB x AD = AC x AE [= AF * ] PROPOSITION XXIII 220. Theorem. If two chords intersect within a circle, the product of the segments of one equals the product of the segments of the other. Dem. x = Y A=D &AEC DEB AE:CE=DE: BE AE x BE = CE... | |
| Webster Wells - Geometry - 1898 - 284 pages
...(2) from (1), we have \ PROP. XXVIII. THEOREM. 280. If any two chords be drawn through a fixed point within a circle, the product of the segments of one...equal to the product of the segments of the other. Given AB and A'B' any two chords passing through fixed point P within O AA'B. To Prove AP x BP = A'P... | |
| Webster Wells - Geometry - 1899 - 424 pages
...Adding (1) and (2), we have PROP. XXVIII. THEOREM. 280. If any two chords be drawn through a fixed point within a circle, the product of the segments of one...equal to the product of the segments of the other. Given AB and A'B' any two chords passing through fixed point P within O AA'B. To Prove AP x BP = A'P... | |
| Webster Wells - Geometry - 1899 - 450 pages
...278) (§ 277) (1) (2) PROP. XXVIII. THEOREM. 280. If any two chords be drawn through a fixed point within a circle, the product of the segments of one...equal to the product of the segments of the other. Given AB and A'B' any two chords passing through fixed point P within O AA'B. To Prove AP x BP = A'P... | |
| Edward Brooks - Geometry, Modern - 1901 - 278 pages
...III. 18. Hence, A EBD is similar to A ECA. Th. 20. Whence, AE : DE =• EC : EB. Def. 5. COR. — Tlie product of the segments of one chord is equal to the product of the segments of the other. For from the preceding proportion we have AE x EB = DE x EC. PROPOSITION XXXII. — THEOREM. If from... | |
| Universities and colleges - 1917 - 140 pages
...congruent if the three sides of one are equal, respectively, to the three sides of the other. 2. a) Prove: If two chords intersect within a circle, the product of the segments of one is equal to the product of the segments of the other. b~) A and B are two points on a railway curve... | |
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