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" Therefore, any term of the progression is equal to the first term multiplied by the ratio raised to a power 1 less than the number of the term. "
Elements of Algebra - Page 202
by William Smyth - 1830 - 264 pages
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The Common School Arithmetic: Prepared for the Use of Academies and Common ...

Charles Davies - Arithmetic - 1833 - 284 pages
...&c. for the other terms. But 2x2=23,2x2x2=23, and 2x2x2x2=2*. Therefore, any term of a progression is equal to the first term multiplied by the ratio raised to a power" 1 less than the number of the term. CASE I. § 230. Having given the first term, the common ratio,...
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Elements of Algebra: Tr. from the French of M. Bourdon. Revised and Adapted ...

Charles Davies - Algebra - 1835 - 378 pages
...find the values of all those which precede it. That is, the last term of a geometrical progression is equal to the first term multiplied ' by the ratio raised to a power whose exponent is one less than the number of terms. For example, the 8lh term of the progression 2...
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Mental and Practical Arithmetic

Charles Davies - Arithmetic - 1838 - 292 pages
...the other terms. But2x2 = 22, 2x2 x 2 = 23, and 2x2x2x2=2*. Therefore, any term of the progression is equal to the • first term multiplied by the ratio raised to a power 1 less ' than the number of the term. Q. In every Geometrical Progression, how many things are considered?...
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Elements of Algebra

Algebra - 1838 - 372 pages
...obliged to find all the terms which precede it. That is, the last term of a geometrical progression is equal to the first term multiplied by the ratio raised to a power whose exponent is one less than the number of terms. 1. Find the 5th term of the progression 2 : 4...
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A New System of Arithmetic: In which is Explained and Applied to Practical ...

Calvin Tracy - Arithmetic - 1840 - 316 pages
...3, 3 is evidently to be taken as multiplier, or factor, eleven times ; that is, any term of a series is equal to the first term multiplied by the ratio raised to a power one less than the number of terms. Thus, 2 x 3 x 3 x 3x3x3x3x3x3x3x3x3" = 3x2= 354294, Ans-. or twelfth...
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Arithmetic, designed for academies and schools, with answers

Charles DAVIES (LL.D.) - Arithmetic - 1843 - 348 pages
...&c. for the other terms. But 2x2=22, 2x2x2=23, and 2x2x2x2=2*. Therefore, any term of the progression is equal to the first term multiplied by the ratio raised to a power 1 less than the number of the term. Q. In every Geometrical Progression, how many things are considered...
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Elements of Arithmetic and Algebra: For the Use of the Royal Military College

William Scott - Algebra - 1844 - 568 pages
...1. Whence the exponent of q in any term is indicated by the number of preceding terms, and any term whatever is equal to the first term multiplied by the ratio raised to a power marked by the number of the terms which precede the term proposed. The formula l=aq~~l 1 is called...
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Arithmetic: Designed for Academies and Schools,(with Answers.)

Charles Davies - Arithmetic - 1844 - 356 pages
...&c. for the other terms. But2x2=22, 2x2x2=23, and 2x2x2x2=24. Therefore, any term of the progression is equal to the first term multiplied by the ratio raised to a power 1 less than the number of the term. Q. In every Geometrical Progression, how many things are considered...
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Elements of Algebra: Including Sturms' Theorem

Charles Davies - Algebra - 1845 - 382 pages
...being obliged to find all the terms which precede it. That is, Any term of a geometrical progression is equal to the first term multiplied by the ratio raised to a power whose exponent denotes the number of preceding terms. EXAMPLES. 1. Find the 5th term of the progression...
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The University Arithmetic: Embracing the Science of Numbers, and Their ...

Charles Davies - Arithmetic - 1846 - 378 pages
...x 2 = 2*, 2 x 2 x 2 = 23, and 2 x 2 x 2 x 2 = 2". Therefore, any term of the progression is ecyjal to the first term multiplied by the ratio raised to a power 1 less than the number of the term. CASE I. Having given the first term, the common ratio, and the...
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