 | Enoch Lewis - Algebra - 1826 - 180 pages
...above remainder by this defective divisor, and annex the result both to the root and to the divisor. Multiply the divisor thus completed by the term of the root last obtained, and subtract the product from the former remainder. Divide the first term of the remainder... | |
 | Bewick Bridge - Algebra - 1832 - 220 pages
...the dividend by double the root already found and set the result both in the root and in the divisor. Multiply the divisor thus completed by the term of...found, and subtract the product from the dividend, and во on as in common arithmetic. Ex. 1. 4Ж* fn ,. . 89 4 4ха+Зж+5) 202:0+ 15Ж+25 Ex. 2. xe+4xs+2x*+9x3—4x+4^X3+... | |
 | Ebenezer Bailey - Algebra - 1835 - 258 pages
...to the root already found and to the divisor. 6. Multiply the divisor, thus increased, by the figure of the root last found, and subtract the product from the dividend. 7. Bring down the next two figures of the given number for a new dividend. 8. Double the whole root... | |
 | Bewick Bridge - Algebra - 1839 - 280 pages
...Divide the dividend by double the root already found, and set the result both in the root and divisor. Multiply the divisor thus completed by the term of...found, and subtract the product from the dividend, and so on. In this manner the following Examples are solved. Ex.1. 4x4+6x2+^x2+15x+25(2^+?x+5 6^+ 20x2+15x+25... | |
 | Horatio Nelson Robinson - Algebra - 1846 - 276 pages
...and set the result both in the root and in the divisor. Multiply the divisor, thus completed, by tJie term of the root last found, and subtract the product from the dividend, and so on. EXAMPLES. 1. What is the square root of )4a3J-f-463 2. What is the square root of l_4J-|_4J3+2y—... | |
 | Horatio Nelson Robinson - Algebra - 1848 - 354 pages
...dividend by double of the root a/ready found, and set the result both in the root and in the divisor. Multiply the divisor, thus completed, by the term of the root last found, and subtract the product fromthe dividend, and so on. EXAMPLES. 1. What is the square root of a4+4a26+462— 4a2— 86-r-4(a2+26—... | |
 | Horatio Nelson Robinson - Algebra - 1850 - 256 pages
...dividend 'by double of the root already found, and set the result both in the root and in the divisor. Multiply the divisor, thus completed, by the term...found, and subtract the product from the dividend, and so on. EXAMPLES. 1 . What is the square root of a4+4a26+462— 4a2— 86+4(a2+26— 2 a4 2a2+2i )~... | |
 | Horatio Nelson Robinson - Algebra - 1850 - 358 pages
...dividend by double of the root already found, and set the result both in the root and in the divisor. Multiply the divisor, thus completed, by the term of the root last found, and subtract the productfromthe dividend, and so on. EXAMPLES. 1. What is the square root of a 4 +4a%+46 2 —4a-—86+4(a... | |
 | William Smyth - Algebra - 1851 - 272 pages
...quotient will be the second term of the root, which place in the root and also in the divisor. 4°. Multiply the divisor thus completed by the term of...found, and subtract the product from the dividend, and so proceed. EXAMPLES. 1. Extract the square root of a4 + 4a3a; + 6 aV + 4 aa? -\- x\ ANS. a? -\- 2... | |
 | William Smyth - Algebra - 1858 - 386 pages
...quotient will be the second term of the root, which place in the root and also in the divisor. 4°. Multiply the divisor thus completed, by the term of...found, and subtract the product from the dividend, und so proceed. EXAMPLES. 1. Extract the square root of a4 -j- 4 a3x + 6 a2z2 + 4 az> + a;4. ANS. o?... | |
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Subtract the square of the root thus found from the first term, and bring down the next two terms for a dividend. III. Divide the first term of the dividend by twice the root already found, and write the result both in the root and in the divisor. IV.... 
