 | Wardhaugh Thompson - 1771 - 324 pages
...hundred pounds for a year, or ia months. SECTION ift. To find the Interelt of any given fum, for a year. Rule. Multiply the Principal by the rate per Cent, and divide that product by 100 ; and the quotient ij the Intereft required. Note, If the Intereft be required... | |
 | Michael Walsh - Arithmetic - 1807 - 290 pages
...Hate, is the sum per cent.-agreed on. Amount, is the principal and interest added together. GENERAL RULE. Multiply the principal by the rate per cent, and divide the product by 100, and the quotient is the answer for one year.. EXAMPLES. 1 . What is the interest of ¿£.496 for one... | |
 | Elijah H. Hendrick - Arithmetic - 1810 - 220 pages
...Simple and Compound.!, SIMPLE INTEREST is that which arifes from the principal only. General Rule. I. Multiply the principal by the rate per cent, and divide the product by loo, (or, which is the fame, cut-off two right hand figures in the pounds, which mint be reduced to... | |
 | Zachariah Jess - Arithmetic - 1810 - 222 pages
...only. CASE 1. When tfcfc time is any number of years, asd the rate per cent, pounds or dollars only ; RULE. Multiply the principal by the rate per cent, and divide the produél by 1 00, the quotient will be the interest for one year ; which multiply by the years given.... | |
 | Arithmetic - 1811 - 210 pages
...interest. CASE*1!. When the time is one year, and the rate per cent, is pounds or dollars only. * • RULE.» Multiply the principal by the rate per cent, and divide the product by 100. PROOF. , , By the Single Rule of Three. EXAMPLES. 1. What is the interest of 525 L. for 1 year, at... | |
 | Nathan Daboll - Arithmetic - 1813 - 244 pages
...Rate, is the sum per cent, agreed on. Amr»vnt is the Drincipal and interest added together. CASE 1. To find the interest of any given sum for one year....— Multiply the principal by the rate per cent, and diviQB UM product by 100 ; the quotient will bo the answer. i EXAMPLES. 1. What is the interest of... | |
 | Nathan Daboll - Arithmetic - 1815 - 250 pages
...sum lent. Rate, is the sum percent, agreed on, Amount, is the principal and interest added together. CASE I. To find the interest of any given sum for...product by 100 ; the quotient will be the answer. EXAMPLE!. 1. What is the interest of 39Z. lls. 8id. for one year at 61. per cent, per annum ? £':... | |
 | Nathan Daboll - Arithmetic - 1817 - 252 pages
...li•nt. Rate, is the sum per cent agreed on. Amount, is the principal and interest added together. . . CASE I. To find the interest of any given sum for...be the answer. EXAMPLES. 1. What is the interest of 39l. 11s. 8^d. for one year at 61. per cent, per annum ? £. sd 39 11 81 2|37 10 3 20 7|50 12 6|03... | |
 | Nathan Daboll - Arithmetic - 1818 - 246 pages
...lent. Rate, is the sum per cent. agreed on. Amount, is the principal and interest added togetherCASE I. To find the interest of any given sum for one year,...answer. EXAMPLES. 1. What is the interest of 391. Us. 8Jd. for one year, at 61. per cent. per annum P £. sd 39 11 8J 6 2|37 10 3 30 7J50 12 6|03 0|12... | |
 | Nathan Daboll - Arithmetic - 1820 - 254 pages
...sum lent. Rate, is the sum per cent, agreed on. Amount, is the principal and interest added together. CASE I. To find the interest of any given sum for one year, RULE. Multiply the principal by the rate percent and divide the product by 100; the quotient will be the answer. EXAMPLES. 1. What is the interest... | |
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Multiply the principal by the rate per cent, and divide the product by 100 ; the quotient will be the answer. 
