| Adrien Marie Legendre - Geometry - 1819 - 208 pages
...angle BAD = DAC, and that the angle BDA — ADC ; therefore these two last are right angles. Hence, a **straight line drawn from the vertex of an isosceles triangle, to the** middle of the base, is perpendicular to that base, anil divides the vertical angle into two equal parts.... | |
| Peter Nicholson - Architecture - 1823 - 210 pages
...C. 61. COROLLARY 1. — Hence every equilateral triangle is also equiangular. 62. COROLLARY 2. — A **straight line drawn from the vertex of an isosceles triangle to the** middle of the base will bisect the vertical angle, and be perpendicular to the base. THEOREM 12. 63.... | |
| Adrien Marie Legendre - Geometry - 1825 - 224 pages
...angle BAD = DAC, and that the angle BDA = ADC; therefore these two last are right angles, /fence a **straight line drawn from the vertex of an isosceles triangle, to the** middle of the base, is perpendicular to that base, and divides the vertical angle into two equal parts.... | |
| Adrien Marie Legendre, John Farrar - Geometry - 1825 - 280 pages
...angle BAD — DAC, and that the angle BDA = ADC ; therefore these two last are right angles. Hence a **straight line drawn from the vertex of an isosceles triangle, to the** middle of the base, is perpendicular to that base, and divides the vertical angle into two equal parts.... | |
| James Hayward - Geometry - 1829 - 228 pages
...PC, AB, AC ; PB and PC will be equal (41), and AB and AC will therefore be equal; and AG will be a **straight line drawn from the vertex of an isosceles triangle to the** middle of the base; that is—BC is perpendicular to the oblique line AG, when it is perpendicular... | |
| Adrien Marie Legendre - Geometry - 1841 - 235 pages
...angle BAD = DAC, and that the anglf BDA = ADC ; therefore these two last are right angles. Hence a **straight line, drawn from the vertex of an isosceles triangle to the** middle of the base, is perpendicular to that base, and divides the vertical angle into two equal parts.... | |
| Euclides - 1845 - 544 pages
...intersection are together one-third of the squares of the sides of the triangle. 27. Prove that the square of **any straight line drawn from the vertex of an isosceles triangle to the base, is less than the square** of a side of the triangle by the rectangle contained by the segments of the base. 28. If from one of... | |
| Peter Nicholson - Cabinetwork - 1856 - 482 pages
...COROLLARY 1. — Hence every equilateral triangle is also equiangular. в с 62. COROLLARY 2. — A **straight line drawn from the vertex of an isosceles triangle to the** middle of the base will bisect the vertical angle, and be perpendicular to the base. THEOREM 12. 63.... | |
| Robert Potts - Geometry, Plane - 1860 - 380 pages
...the middle segment is equivalent to twice the rectangle under the extreme segments. V. 37. Prove that **the square on any straight line drawn from the vertex...the rectangle contained by the segments of the base** : and conversely. 38. If from one of the equal angles of an isosceles triangle a perpendicular be drawn... | |
| Euclides - 1862 - 140 pages
...straight line which bisects the vertical angle of an isosceles triangle, bisects also the base. 3. The **straight line drawn from the vertex of an isosceles triangle to the** point of bisection of the base, bisects the vertical angle, and is perpendicular to the base. 4. In... | |
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