An Advanced Arithmetic

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Ginn & Company, 1898
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Page 158 - CUBIC MEASURE 1728 cubic inches (cu. in.) = 1 cubic foot (cu. ft.) 27 cubic feet = 1 cubic yard (cu. yd.) 128 cubic feet = 1 cord (cd...
Page 147 - LIQUID MEASURE 4 gills (gi.) = 1 pint (pt.) 2 pints — 1 quart (qt...
Page 314 - Multiply the complete divisor by the second figure of the root, subtract the product from the dividend, and to the remainder annex the next period for a new dividend.
Page 156 - Square Measure 144 square inches (sq. in.) = 1 square foot (sq. ft.) 9 square feet = 1 square yard (sq. yd.) 30 square yards = 1 square rod (sq. rd.) 160 square rods = 1 acre (A.) 640 acres = 1 square mile (sq.
Page 163 - Thirty days hath September, April, June, and November, All the rest have thirty-one Excepting February alone : Which hath but twenty-eight, in fine, Till leap year gives it twenty-nine.
Page 68 - A Circle is a plane figure bounded by a curved line, called the Circumference, all points of which are equally distant from a point within, called the Centre.
Page 219 - That is, in any proportion either extreme is equal to the product of the means divided by the other extreme ; and either mean is equal to the product of the extremes divided by the other mean.
Page 58 - ... measure. 111. The metric system is a system of weights and measures expressed in the decimal scale. 112. The standard meter, as defined by law, is the length of a bar of very hard metal, carefully preserved at Paris, accurate copies of which are furnished the governments of all civilized countries. The meter was intended to be one ten-millionth of the distance from the equator to the north pole, but more careful measurements show that this distance is 10,001,887 meters.
Page 59 - Measures of Length. 10 millimeters (mm.) 1 centimeter (cm.) 10 centimeters 1 decimeter (dm.) 10 decimeters 1 meter (m.) 10 meters 1 dekameter (Dm.) 10 dekameters 1 hectometer (Hm.) 10 hectometers 1 kilometer (Km.) 10 kilometers 1 myriameter (Mm.) 1181.
Page 309 - Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the operation as before, until all the periods are brought down. NOTE.

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