 | Oliver Welch - Arithmetic - 1857 - 244 pages
...together, CASE I. '7V»e principal and rate given, te find the interett for one year, or more, tsfc. RULE, — Multiply the principal by the rate per cent,...that time, in dollars and parts of dollars, Examples. \, What is the interest of $22- 16 cents for one year, at 6 per cent, per annum ? do!*, cts, 22-16... | |
 | John Preston - Arithmetic - 1817 - 538 pages
....2772 [Continued. 2772 2555 .2175 1825 .3500 3285 .215+ RULE POR PROOF. Multiply the principal in cents by the rate per cent, and that product by the number of days for a dividend. Multiply 365 by 100 for a divisor; the quotient will be the answer in cents. 5075... | |
 | Thomas Keith - Arithmetic - 1822 - 354 pages
...multiplied by the number of years given in the question, the product will be the interest for that time. Or, multiply the principal by the rate per cent., and that product by the time; the last product, divided by 100, will give the interest required, Note 1. If there be any parts... | |
 | Oliver Welch - Arithmetic - 1826 - 242 pages
...amount is the principal and interest together. CASE I. The principal and rate given tojind the interest. RULE. — Multiply the principal by the rate per cent....product by the number of years ; the last product printed, according to the rule of decimals, will be the answer for that time, in dollars and parts... | |
 | John White - 1826 - 74 pages
...MONEY, For any Number of Months, Weeks, or Days, and at any Rate per Cent. BY THE FOREGOING TABLE. RULE. Multiply the principal, by the rate per cent, and that product by the number of months, weeks, or days, for •which the interest is required, and then cut off two figures on the... | |
 | Thomas Conkling (W.) - Arithmetic - 1831 - 302 pages
...rated at so much per cent. CASE I. To find the interest of any sum of money, for one, or more years. RULE. Multiply the principal by the rate per cent, and that product by the number of years, then divide the last product by 100; the quotient will be the interest required. * In New York, at... | |
 | Francis Walkingame - 1833 - 204 pages
...the Principal and Interest added together. I. To find the Interest of any Sum of Money for a Year. RULE. Multiply the Principal by the Rate per cent, and that Product divided by 100, will give the Interest required. NOTE. When the Rate is an aliquot part of 10O, the... | |
 | John Preston - Arithmetic - 1834 - 312 pages
...at 7 per cent, per annnm ? Answer, 87.59 cents. Rule for proof . — Multiply the principal in cents by the rate per cent., and that product by the number of days for a dividend. Multiply 3b'5*by 100 for a divisor ; the quotient will be the answer in cents.... | |
 | Francis Walkingame - 1835 - 270 pages
...cent, per annum? Ans. £37 14 8|. RULE II. To find the interest of any sum for several years. Multiply by the rate per cent., and that product by the number of years, and divide by 100 : or, if the rate be 5 per cent., divide the principal by 20, and multiply the quotient... | |
 | Robert Goodacre - 1839 - 320 pages
...interest is not exactly for a year. plication, Compound Division, Practice, Decimals, or Proportion. Or, multiply the principal by the rate per cent, and that product by the time ; the last product divided by 100 will give the interest required. As the rules just mentioned... | |
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RULE. Multiply the principal by the rate per cent, and •that product by the number of years : the last product... 
