 | Paul Deighan - Arithmetic - 1804 - 504 pages
...- 2? 1.189207. 4. — - 3336217176? 76. 5- — — - 5715140625? 275. d general Rule for extrafting the Roots of all Powers.* 1. Prepare the number given...required directs. 2. Find the firft figure in the rqot by the Table of Powers which fubtracl from the given number.. 3. Bring down the firft figure in... | |
 | Nicolas Pike - Algebra - 1808 - 470 pages
...nearlj. Subtract 200X 200-:-4=10000 •V/9025=95 Add half the assumed root = 1 00 Required root 195 A GENERAL RULE FOR EXTRACTING THE ROOTS OF ALL POWERS. * 1. Prepare the given number, for extra&ion, by pointing off from the unit's place, as the required root directs. 2.... | |
 | Michael Walsh - Arithmetic - 1816 - 288 pages
...is the biquadrate root of 33362176? 76. i. What is the biquadrate root of 5719140625 ? 275. " *• t A GENERAL RULE FOR EXTRACTING THE ROOTS Of ALL POWERS. 1. PREPARE the number given for extraction, by poieting : off from tho unit's place as the root required directs. 2. Find the first figure in the... | |
 | James Maginness - Arithmetic - 1821 - 378 pages
...subject familiar enough to any one, to extend it to any length farther that may be thought necessary. A GENERAL RULE FOR EXTRACTING THE ROOTS OF ALL POWERS. 1. Prepare the given number for extraction, by pointing off from the place of unity, as the root required directs.... | |
 | Nicolas Pike, Dudley Leavitt - Arithmetic - 1826 - 214 pages
...diameter of a globe be 6 inches, what will be the diameter of a globe 64 times as large ? Ans. 24 inches. A GENERAL RULE FOR EXTRACTING THE ROOTS OF ALL POWERS.* 1. Prepare the given number for extraction, by pointing off from the units' place, as the required root directs. 2.... | |
 | Nicolas Pike, Dudley Leavitt - Arithmetic - 1826 - 222 pages
...diameter of a globe be 6 inches, what will be the diameter of a globe 64 times as large ? Ans. 24 inches. A GENERAL RULE FOR EXTRACTING THE ROOTS OF ALL POWERS.* 1 . Prepare the given number for extraction, by pointing off from the units, place, as the required root directs. 2.... | |
 | Michael Walsh - Arithmetic - 1828 - 318 pages
...biquadrate of 27 1 Ans. 53144K 2. What is the biquadrate root of 531441 ? Ans. 27. A GENERAL RULE FOK EXTRACTING THE ROOTS OF ALL POWERS. 1. PREPARE the number given for extraction, by pointing off fron> the unit's place as the root required directs. 2. Find the first figure in the root, by the table... | |
 | Michael Walsh - Arithmetic - 1828 - 312 pages
...Aas. 531441. 2. What is the biquadrate root of 531 441? Ans, 27. A GENERAL RULE FOB EXTRACTING THB ROOTS OF ALL POWERS. 1. PREPARE the number given for extraction, by pointing off no* the unit's place as the root required directs. , 2. Find the first figure in Ihe root, by the table... | |
 | Michael Walsh - 1831 - 348 pages
...531441. 2. What is the biquadrate root of 531441 ? Ans. 27. A GENERAL RULE FOR EXTRACTING THE ROOTS OP ALL POWERS. 1. Prepare the number given for extraction,...unit's place as the root required directs. 2. Find the first figure in the root, by the table of powers, which subtract from the given number. 3. Bring down... | |
 | Francis Walkingame - 1832 - 224 pages
...biquadrate root of 5719140625? Ant. 273. A GENERAL RULE FOR EXTRACTING THE ROOTS OF ALL POWERS. 1. "pREPAEE the number given for extraction, by pointing -*- off...unit's place as the root required directs. 2. Find the first figure in the root by the table of powers, which subtract from the given number. 3. Bring down... | |
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A GENERAL RULE FOR EXTRACTING THE ROOTS OF ALL POWERS. 1. Prepare the number given for extraction, by pointing off from the unit's place as the root required directs. 2. Find the first figure in the root, by the table of powers, which subtract from the... 
