 | Roswell Chamberlain Smith - 1814 - 300 pages
...per cent, is $13; hence a« I i years, the requited time, Jiiu. Q. What, then, is the RULE 7 '• A. Divide the given interest by the interest of the principal for 1 year at the given rate ; the quotient Witt be the time required, in years and decinal parts of a year. 2. Paid $36 interest... | |
 | John Preston - Arithmetic - 1817 - 538 pages
...per cent. To find the time when the principal, the rate per cent, and the amount are given, say, " As the interest of the principal for 1 year at the given rate, is to one year ; So id the whole interest, to the time required." LESSOJY 25. In what time will 300... | |
 | Phinehas Merrill - Arithmetic - 1819 - 116 pages
...cent. To find the time, iahen the firinci/ial, amount andratefier cent^ . , . are five*. RULE.— As the. interest of the principal for 1 year at the given rate, is to 1 year, so h the whole interest to the time required. EXAMPLES. 1. In what time will L.500 amount... | |
 | Roswell Chamberlain Smith - Arithmetic - 1830 - 286 pages
...1¿ yearз, the required time, Ans. * Q. What, then, is the RULE ? A. Divide the given interest Ъу the interest of the principal for 1 year at the given rate, the quotient will be the time required, in years and decimal parts of a year. 2. Paid $36 interest... | |
 | Roswell Chamberlain Smith - Arithmetic - 1831 - 286 pages
...Лепи $18 -H 12 = If *"•• I ,'¿ year«, the required time, .fins. Q. What, then, is the RULE ? A. Divide the given interest by the interest of the principal for 1 year at the given rate, the quotient will bo the time required, in years and decimal parts of a year. 2. Paid $36 interest... | |
 | Zadock Thompson - Arithmetic - 1832 - 182 pages
...$1.35-^-$1.80rr0.75yr.— 4 months (145), die answer. Therefore, s IV. The principal, rate and interest being given, to find the time. RULE. — Divide the given interest by the interest of the given principal for 1 year at the given rate, and the quotient will be the time m years and decimal... | |
 | Zadock Thompson - Arithmetic - 1832 - 186 pages
...months (145), the answer. Therefore, ... j \ I V. The principal, rate and interest being given, tofind the time. RULE.— Divide the given interest by the interest of the given principal for 1 year at the given rale, and the quotient will be the time m years and decimal... | |
 | Roswell Chamberlain Smith - 1839 - 308 pages
...$13; hence 818 — 12=-. 1,.'. - ..\l. years, the required time, Jinn. Q. What, then, is the RULE 1 A. Divide the given interest by the interest of the principal for 1 year at the given rate ; the quotient will be the time required, in years and decimal parts of a year. 2. Paid $36 interest... | |
 | Benjamin Greenleaf - Arithmetic - 1839 - 356 pages
...it take 1 year to gain $30, it will require to gain $120, igi° = 4 years Ans. Hence the following RULE. Divide the given interest, by the interest of the principal, for 1 year, and the quotient is the lime. 5. How long must $120 be on interest at 8J per cent. to amount to $133.20... | |
 | Calvin Tracy - Arithmetic - 1840 - 326 pages
...the rate per cent. 1 Ans. 4 per cent. Prob. 37. Given the principal, rate per cent., and interest, to find the time. RULE. — Divide the given interest by the interest of the principal for one year ; the quotient will be the time. Ex. 1. Paid $108 interest on a note of $600. How long had... | |
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Or, make the given interest the numerator, and the interest of the principal for 1 year at the given rate the... 
