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" Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the area. "
The new practical gager - Page 62
by Matthew Iley - 1820
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The American Tutor's Guide: Being a Compendium of Arithmetic. In Six Parts ...

James Thompson - Arithmetic - 1808 - 176 pages
...area of a trafiezoid, or quadrangle, <u'o cf •whose opposite sides are parallel. RULE — Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product •will be the area. EXAMPLES. 13. Required the area of a trapezoid whose parallel...
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The principles of architecture, Volume 1

Peter Nicholson - 1809 - 426 pages
...BF. 14 X36 84 42 504=the area of ABCD. PROBLEM VI. To find the area of a trapezoid. Multiply the half sum of the parallel sides by the perpendicular distance between them, and the product will be the area. EXAMPLE I. What is fhe area of a board or plank in the form of a trapeziod, being 1f. 7i. one end,...
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The complete measurer: or, The whole art of measuring, containing the ...

Thomas Keith - 1817 - 306 pages
...perches. PROBLEM VIII. • To find the Area of a Trapezoid. RULE *. Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will be the area. Example 1. Let AB c D JE. be a trapezoid, the side '-. A )•. — 23, D c = 9•5, and CI — 13,...
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A Treatise on Practical Mensuration in Eight Parts ...

Anthony Nesbit - Surveying - 1824 - 476 pages
...is its area ? Ans. 1131^.2 in. 9 pa. PROBLEM VIII. To find the area of a Irapezoid. RULE. Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the area. Or, half the sum of the sides multiplied by their distance will...
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A Popular Course of Pure and Mixed Mathematics ...: With Tables of ...

Peter Nicholson - Mathematics - 1825 - 1046 pages
...42 501 = the arca of ABCD. MENSURATION. Prob. 6. To find the area of a trapezoid. Multiply the half sum of the parallel sides by the perpendicular distance between them, and the product will be the area. Ex. 3. What is the area of a board or plank in the form of a trapezoid, being If. 7¡- at one end,...
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The Youth's Assistant in Theoretick and Practical Arithmetic

Zadock Thompson - Arithmetic - 1826 - 176 pages
...54.299 rods. I Problem III. Tojind the area of a trapezoid. :BuLE.— Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will be the area. Examples. 1. One of the two parallel sides of a trapezoid is 7.5 chains and the other 12.25, and the...
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A Treatise on the New Method of Land Surveying, with the Improved Plan of ...

Thomas Hornby (land surveyor.) - Surveying - 1827 - 318 pages
...00000000 2.40000 40 16.00000 Ans. 0A. 2n. 16p. PROBLEM 3. To find the Area of a Trapezoid. RULE. Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the area. EXAMPLE. Required the area of the trapezoid AB CD, whose parallel...
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An Introduction to Mensuration and Practical Geometry

John Bonnycastle - Geometry - 1829 - 256 pages
...the area of a trapezoid, or a quadrangle, two of whose opposite sides are parallel. RULE.* Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the EXAMPLES. 1. Required the area of the trapezoid ABCD, whose sides AB and...
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The Edinburgh encyclopaedia, conducted by D. Brewster, Volume 14

Edinburgh encyclopaedia - 1830 - 856 pages
...trapezoid is a quadrilateral, of which two opposite sides are parallel but not equal. RULE. Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product is the area. In the trapezoid ABCD, draw the diagonal AC, and from its extremities...
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A Concise System of Mathematics ...

Alexander Ingram - Mathematics - 1830 - 458 pages
...acres 3 roods 21 perches 26 yards 5 feet. QUADRILATERALS. Piion. VII. To find the area of a trapeziod. RULE. Multiply half the sum of the parallel sides by the perpendicular from the one to the other. For the triangles into which it may be divided have the same perpendicular....
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