 | Arithmetic - 1818 - 264 pages
...orbit be 596,902,10<} miles how far are we from the Sun ? Ans. 95,000,000miles. PROBLEM VII. To Jind the Area of a circle. RULE. Multiply the square of the diameter by .7854 OR Multiply half the diameter into half the circumference. Ex. I. What is the area of a circle... | |
 | Nautical astronomy - 1821 - 708 pages
...429 feet ; this added to the triangle AEB 143 feet, gives the whole area 572 square feet. PROBLEM IV. To find the area of a circle. RULE. Multiply the square of the diameter of the circle by the quantity 0.7854, and yeu will have the sought area. NOTE. Instead of multiplying... | |
 | Nathaniel Bowditch - Nautical astronomy - 1826 - 764 pages
...BODE, 429 feet ; this added to the triangle j gives the whole area 572 square feet. PROBLEM IV. Toßnd the area of a circle. RULE. Multiply the square of the diameter of the circle bj 0.7854, and you will have the sought area. NOTE. Instead of multiplying hy 0.7854... | |
 | Nathaniel Bowditch - Nautical astronomy - 1826 - 732 pages
...this added to the triangle ЛЕВ 143 feet,' gives the whole area Ü72 square feet. PROBLEM IV. Toßnd the area of a circle. RULE. Multiply the square of the diameter of the circle by the quantit v 0.7854, and you will Imve the sought area. NOTE. Instead of multiplying... | |
 | Daniel Parker - Arithmetic - 1828 - 358 pages
...Ans. 2. What is the mean proportional between 15 and 60 ? 60X15=900 ; and ^900=30 JÎn». PROB. V. — To find the area of a circle, Rule. — Multiply the square of the diameter by ,7854, and the product will be the area. Or, multiply the square of the circumference by ,07958, and... | |
 | George Willson - Arithmetic - 1836 - 202 pages
...side being 2 yards,) then a circle of 2 yards in diameter, would contain .7854 X 4 = 3.1416 yards. RULE. — Multiply the square of the diameter by the decimal .7854, and the product is the area. When the circumference of a circle is known, the diameter may be found by the following... | |
 | George Willson - Arithmetic - 1838 - 194 pages
...(its side being 2 yards,) then a circle of 2 yards in diameter, would contain .7854 X 4=3.1416 yards. RULE. — Multiply the square of the diameter by the decimal .7854, and the product is the area. When the circumference of a circle is known, the diameter may be found by the following... | |
 | Calvin Tracy - Arithmetic - 1842 - 306 pages
...Ans. 2. What is the diameter of a wheel whose circumference is 50 feet ? Ans. 15.9 +feet. PROB. 14. To find the area of a circle. RULE. — Multiply the square of the DIAMETER by the decimal .7854, or by the fraction -f^-; or, multiply the square of the CIRCUMFERENCE by the decimal .07958. Ex. 1.... | |
 | J. M. Scribner - Measurement - 1844 - 130 pages
...feet. Ans. 7.058 ft. PROBLEM V. To find the area of a Circle when the Diameter only is known. ART. 21. Rule. — Multiply the square of the diameter by the decimal .7854, and the product will be the area. Ex. 1. What is the area of a circle whose diameter is 11 feet? OPERATION. 11= 12 Ix. 7854=95.0334,... | |
 | Almon Ticknor - Arithmetic - 1846 - 276 pages
...chains ; what is the diameter? Ans. 5.0929+chains. The diameter given, to find the area or content. RULE. Multiply the square of the diameter by the decimal .7854, and the product will be the area. 1. How many square feet are contained in a circle, whose diameter is 4 feet 3 inches ? Thus : 4.252... | |
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TO FIND THE AREA OF A CIRCLE. Rule. — Multiply the square of the diameter by .7854 and the product will be the area. 
