The new practical gager1820 |
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Page 28
... wine gallons . 2. AG at 18.95 the circular gage point for ale gallons . 3. MS at 46.37 the square gage point for malt bushels . 4. MR at 52-32 the circular gage point for malt bushels . The second line on this face is the line C on the ...
... wine gallons . 2. AG at 18.95 the circular gage point for ale gallons . 3. MS at 46.37 the square gage point for malt bushels . 4. MR at 52-32 the circular gage point for malt bushels . The second line on this face is the line C on the ...
Page 118
... Wine - gallon , the Ale- gallon , and the Malt - bushel , Cubic Inches The wine gallon 231 [ W.G. The ale gallon ... gallons . square 282 Ale - gallons . root of 2150-42 46-37 ) point for Malt - bushels . The numbers themselves are ...
... Wine - gallon , the Ale- gallon , and the Malt - bushel , Cubic Inches The wine gallon 231 [ W.G. The ale gallon ... gallons . square 282 Ale - gallons . root of 2150-42 46-37 ) point for Malt - bushels . The numbers themselves are ...
Page 119
... wine gal- lons , ale - gallons , and malt - bushels . F H SOLUTION BY THE PEN . 90 side of the 90 side square W.G. divisor 231 ) 8100 ( 35-06 wine gallons . A. G. divisor 282 ) 8100 ( 28-72 ale gallons . M.B. divisor 2150 ) 8100 ( 3.76 ...
... wine gal- lons , ale - gallons , and malt - bushels . F H SOLUTION BY THE PEN . 90 side of the 90 side square W.G. divisor 231 ) 8100 ( 35-06 wine gallons . A. G. divisor 282 ) 8100 ( 28-72 ale gallons . M.B. divisor 2150 ) 8100 ( 3.76 ...
Page 120
... wine - gallons , ale - gallons , and malt - bushels ? SOLUTION BY THE PEN . 76.4 side of the square 76.4 side 3056 4584 5348 W.G. divisor 231 ) 5836.96 ( 25.26 wine gallons . A. G. divisor 282 ) 5836-96 ( 20-69 ale gallons . M.B. ...
... wine - gallons , ale - gallons , and malt - bushels ? SOLUTION BY THE PEN . 76.4 side of the square 76.4 side 3056 4584 5348 W.G. divisor 231 ) 5836.96 ( 25.26 wine gallons . A. G. divisor 282 ) 5836-96 ( 20-69 ale gallons . M.B. ...
Page 121
... wine - gallons , ale- gallons , and malt - bushels . SOLUTION BY THE PEN . 35 breadth of the rectangle 80 length W.G. divisor 231 ) 2800 ( 12-12 wine gallons . A. G. divisor 282 ) 2800 ( 9.93 ale gallons . M.B. divisor 2150 ) 2800 ...
... wine - gallons , ale- gallons , and malt - bushels . SOLUTION BY THE PEN . 35 breadth of the rectangle 80 length W.G. divisor 231 ) 2800 ( 12-12 wine gallons . A. G. divisor 282 ) 2800 ( 9.93 ale gallons . M.B. divisor 2150 ) 2800 ...
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Common terms and phrases
30 inches A. G. divisor 282 ale gallons altitude area is required base bottom bung diameter Cask centre chord circular divisor circular gage-point Circular Segments conjugate diameter content is required Copper cross diameters crown cube cubic inches denomination determine the Content Diam diameter Multiply Dimension Book dipping place distance divide the product dividend division dry inches ellipsis equal EXAMPLE factor find the Area frustum Gage and Inch given figure given number greatest diameter inch deep inch in depth Lastly Let ABCD malt bushels mean diameter mean proportional measure middle mouth number of cubic opposite ordinates parabolic parallel perpendicular plane figure proposed integer quotient radius remainder required in wine Set the circular side SLIDING RULE SOLUTION Specific Gravity square inches square root straight line subtract sum Multiply tabular number tenths transverse diameter triangle ullage vulgar fraction Wet Inches Wherefore whole content wine gallons
Popular passages
Page 39 - To draw a straight line perpendicular to a given straight line of an unlimited length, from a given point without it. Let AB be the given straight line, which may be produced to any length both ways, and let c be a point without it.
Page 27 - A diameter of a circle is a straight line drawn through the centre, and terminated both ways by the circumference.
Page 62 - Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the area.
Page 56 - To measure a Parallelogram, or long square. RULE. Multiply the length by the breadth, and the product will be the area or superficial content.
Page 65 - TO FIND THE AREA OF A CIRCLE. Rule. — Multiply the square of the diameter by .7854 and the product will be the area.
Page xv - Separate the given number into periods of two figures each, beginning at the right hand: the period on the left will often contain but one figure.
Page 40 - To bisect a given finite straight line, that is, to divide it into two equal parts. Let AB be the given straight line : it is required to divide it intotwo equal parts.
Page 37 - At a given point in a given straight line, to erect a perpendicular to that line. Let AB be the given line and C the given point.
Page iii - EULE.—Divide as in whole numbers, and point off as many decimal places in the quotient as the number of decimal places in the dividend exceeds the number in the divisor.
Page 32 - A cylinder is conceived to be generated by the revolution of a rectangle about one of its sides as an axis.