The new practical gager1820 |
From inside the book
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Page 17
... opposite to each de- nomination write , for divisor , the number of units which of that denomination makes a unit of the next higher : proceed now to divide , placing the quotients as deci- mals of the next higher denominations ...
... opposite to each de- nomination write , for divisor , the number of units which of that denomination makes a unit of the next higher : proceed now to divide , placing the quotients as deci- mals of the next higher denominations ...
Page 28
... , viz . , from 1 to 3.162 being placed on one side of C , and the other part of it , that is , from 3.162 to 10 , being situate on the opposite side of C. Lines on the Third and Fourth Faces of the Rule 28 SLIDING RULE .
... , viz . , from 1 to 3.162 being placed on one side of C , and the other part of it , that is , from 3.162 to 10 , being situate on the opposite side of C. Lines on the Third and Fourth Faces of the Rule 28 SLIDING RULE .
Page 32
... opposite to 9 on B you have 63 on A : or set 1 on B to 9 on A , and against 7 on B you again have 63 on A. Here it may be proper to observe that it frequently happens that , when 1 on B is set to the given number on A , the other number ...
... opposite to 9 on B you have 63 on A : or set 1 on B to 9 on A , and against 7 on B you again have 63 on A. Here it may be proper to observe that it frequently happens that , when 1 on B is set to the given number on A , the other number ...
Page 33
... opposite to the number on A at which 1 ought to stand . This having been done , 10 on B now counting for 1 , we readily discover opposite to 85 on B , 1190 on A , for the tenth part of the product ; and consequently the whole product is ...
... opposite to the number on A at which 1 ought to stand . This having been done , 10 on B now counting for 1 , we readily discover opposite to 85 on B , 1190 on A , for the tenth part of the product ; and consequently the whole product is ...
Page 34
... opposite the thou- sandth part of 8500 on A. Now on B , opposite to 8.5 on A , we find 1 · 7 as the thousandth part of the quotient , and consequently the whole quotient is 1700 . If 5 were given to be divided by 8500 , we should set 1 ...
... opposite the thou- sandth part of 8500 on A. Now on B , opposite to 8.5 on A , we find 1 · 7 as the thousandth part of the quotient , and consequently the whole quotient is 1700 . If 5 were given to be divided by 8500 , we should set 1 ...
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Common terms and phrases
30 inches A. G. divisor 282 ale gallons altitude area is required base bottom bung diameter Cask centre chord circular divisor circular gage-point Circular Segments conjugate diameter content is required Copper cross diameters crown cube cubic inches denomination determine the Content Diam diameter Multiply Dimension Book dipping place distance divide the product dividend division dry inches ellipsis equal EXAMPLE factor find the Area frustum Gage and Inch given figure given number greatest diameter inch deep inch in depth Lastly Let ABCD malt bushels mean diameter mean proportional measure middle mouth number of cubic opposite ordinates parabolic parallel perpendicular plane figure proposed integer quotient radius remainder required in wine Set the circular side SLIDING RULE SOLUTION Specific Gravity square inches square root straight line subtract sum Multiply tabular number tenths transverse diameter triangle ullage vulgar fraction Wet Inches Wherefore whole content wine gallons
Popular passages
Page 39 - To draw a straight line perpendicular to a given straight line of an unlimited length, from a given point without it. Let AB be the given straight line, which may be produced to any length both ways, and let c be a point without it.
Page 27 - A diameter of a circle is a straight line drawn through the centre, and terminated both ways by the circumference.
Page 62 - Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the area.
Page 56 - To measure a Parallelogram, or long square. RULE. Multiply the length by the breadth, and the product will be the area or superficial content.
Page 65 - TO FIND THE AREA OF A CIRCLE. Rule. — Multiply the square of the diameter by .7854 and the product will be the area.
Page xv - Separate the given number into periods of two figures each, beginning at the right hand: the period on the left will often contain but one figure.
Page 40 - To bisect a given finite straight line, that is, to divide it into two equal parts. Let AB be the given straight line : it is required to divide it intotwo equal parts.
Page 37 - At a given point in a given straight line, to erect a perpendicular to that line. Let AB be the given line and C the given point.
Page iii - EULE.—Divide as in whole numbers, and point off as many decimal places in the quotient as the number of decimal places in the dividend exceeds the number in the divisor.
Page 32 - A cylinder is conceived to be generated by the revolution of a rectangle about one of its sides as an axis.