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" The lateral area of a frustum of a cone of revolution is equal to one-half the sum of the circumferences of its bases multiplied by its slant height. Hyp. S is the lateral area, C and C... "
Plane [and Spherical] Trigonometry for Colleges and Secondary Schools - Page 55
by Daniel Alexander Murray - 1908
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A Treatise on Elementary Geometry: With Appendices Containing a Collection ...

William Chauvenet - Geometry - 1871 - 380 pages
...altitudes, or as the squares of the radii of their bases. /"r\ -.vA-.y PROPOSITION VI.— THEOREM. >.. 26. The lateral area of a frustum of a cone of revolution is equal to the half sum of the circumferences of its bases multiplied by its slant height. The plane which cuts off...
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A Treatise on Elementary Geometry: With Appendices Containing a Collection ...

William Chauvenet - Geometry - 1871 - 380 pages
...the number of whose faces is indefinitely increased. PROPOSITION V.— THEOREM. 23. The lateral area of a cone of revolution is equal to the product of the circumference of its base by half its slant height. Let S-MNPQ be a cone generated by the revolution...
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A Treatise on Elementary Geometry: With Appendices Containing a Collection ...

William Chauvenet - Geometry - 1872 - 382 pages
...of their altitudes, or as the squares of the radii of their bases. PROPOSITION VI.— THEOREM. 26. The lateral area of a frustum of a cone of revolution is equal to the half sum of the circumferences of its bases multiplied by its slant height. The plane which cuts off...
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A Treatise on Elementary Geometry: With Appendices Containing a Collection ...

William Chauvenet - Mathematics - 1872 - 382 pages
...the number of whose faces is indefinitely increased. PROPOSITION V.— THEOREM. 23. The lateral area of a cone of revolution is equal to the product of the circumference of its base by half its slant height. Let S-MNPQ be a cone generated by the revolution...
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Annual Statement, Volumes 11-20

1876 - 646 pages
...are mutually equiangular they are also mutually equilateral ; and are either equal or symmetrical. 8. The lateral area of a frustum of a cone of revolution is equal to the half sum of the circumferences of its bases multiplied by its slant height. ENGLISH GRAMMAR. JUNE,...
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Elements of Plane and Solid Geometry

George Albert Wentworth - Geometry - 1877 - 416 pages
...frustum of a cone of revolution. Draw CHI-, and AD II, to YY'. Then area AB = AB X 2 jr СH, §662 (the lateral area of a frustum of a cone of revolution is equal to the slant height multiplied 'by the circumference of a section equidistant from its bases). The AABD and...
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Elements of Plane and Solid Geometry

George Albert Wentworth - Geometry - 1877 - 436 pages
...revolution. Draw Cff±, and AD II, to Y Y'. Then area AB = AB X 2 тг С Н, §662 (the lateral arca of a frustum of a cone of revolution is equal to the slant height multiplied by the circumference of a section equidistant from its bases). The AABD and...
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Yale Examination Papers

F. B. Stevens - Examinations - 1884 - 202 pages
...mutually equiangular, they are also mutually equilateral ; and are either equal or symmetrical. 8. The lateral area of a frustum of a cone of revolution is equal to the half sum of the circumferences of its bases multiplied by its slant height. June, 1882. NOTE 1. Candidates...
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The Elements of Geometry

George Bruce Halsted - Geometry - 1885 - 389 pages
...basal radii rl and r2 find the radius of the circle in which the two cones cut. 329 THEOREM III. 832. The lateral area of a frustum of a cone of revolution is the product of the projection of the frustum s slant height on the axis by twice TT times a perpendicular...
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The Elements of Geometry

George Bruce Halsted - Geometry - 1886 - 394 pages
...basal radii r, and r, find the radius of the circle in which the two cones cut. 329 THEOREM III. 832. The lateral area of a frustum of a cone of re-volution is the product of the projection of the frustums slant height on the axis by twice ?r times a perpendicular...
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