...and the solidity of the cylinder will be rR*xH, or »/?*//. MMMA. 520. The convex surface of a right prism is equal to the perimeter of its base multiplied by its altitude. Demonstration. This surface is equal to the sum of the rectangles AFGB, BGHC, CHID, &c. (j%. 25S),...

...the perimeter of the prism's base. Hence the sum of these rectangles, or the convex surface of the prism, is equal to the perimeter of its base, multiplied by its altitude. Cor. If two right prisms have the same altitude, their convex surfaces will be to each other as the...

...equal to the altitude of the prism. Therefore the sum of these rectangles, or the convex surface of the prism, is equal to the perimeter of its base multiplied by its altitude. 521. Corollary. If two right prisms have the same altitude, the convex surfaces of these prisms will...

...equal to the altitude of the prism. Therefore the sum of these rectangles, or the convex surface of the prism, is equal to the perimeter of its base multiplied by its altitude. 521. Corollary. If two right prisms have the same altitude, the convex surfaces of these prisms will...

...its altitude. Now it has already been demonstrated, lemma 520, that ' the convex surface of a right prism, is equal to the perimeter of its base multiplied by its altitude.' Admitting, then, our principle, the convex surface of a cylinder will consist of an infinite number...

...its altitude. Now it has already been demonstrated, lemma 520, that ' the convex surface of a right prism, is equal to the perimeter of its base multiplied by its altitude.' Admitting, then, our principle, the convex surface of a cylinder will consist of an infinite number...

...and having like inclinations with each other. PROPOSITION I. THEOREM. The convex surface of a right prism is equal to the perimeter of its base multiplied by its altitude. Let ABCDE-K be aright prism : then will its convex surface be equal to (AB + BC + CD + DE+EA)xAF. For,...

...and having like inclinations with each other. PROPOSITION I. THEOREM. The convex surface of a right prism is equal to the perimeter of its base multiplied by its al1iiude. Let ABCDE-K be aright prism : then will its convex surface be equal to (AB + BC + CD + DE+EA)xAF....

...the solidity of the cylinder will be * W x If, or * IPH. LEMMA. 520. The convex surface of a right prism is equal to the perimeter of its base multiplied by its altitude. Demonstration. This surface is equal to the sum of the rectangles AFGB, BGHC, CHID, &c. (fig. 252),...

...base, is also equal to that base. PROPOSITION V. THEOREM. The convex surface of a right prism ACEFHK, is equal to the perimeter of its base multiplied by its altitude AF. For, since the sides of a right prism are K perpendicular to its base ; (Def. 7. 7 ;) all its lateral...