| Edward Albert Bowser - Geometry - 1890 - 418 pages
...(340) .-.PBX PA = PEXPD. (Ax. 1) Therefore, if from a point without a circle two secants be drawn, the product of one secant and its external segment is equal to the product of the other and its external segment. 342. COR. 3. If from a point without a circle any nmnber of secants are drawn,... | |
| George Albert Wentworth, George Anthony Hill - Geometry - 1894 - 150 pages
...Theorem. If two secants are drawn from a point to a circle, the product of one secant and its exterior segment is equal to the product of the other secant and its exterior segment. 235. Theorem. If from a point without a circle a tangent and a secant are drawn to... | |
| Andrew Wheeler Phillips, Irving Fisher - Geometry - 1896 - 554 pages
...Therefore PB' x PA ' = PB x PA . Ax. i Hence, if from a point wit '/tout a circle two secants be drawn, the product of one secant and its external segment is equal to the product of the other and its external segment. 323. Exercise.— Prove § 322 by drawing A'B and AB' '. 324. Def. — The... | |
| Andrew Wheeler Phillips, Irving Fisher - Geometry, Modern - 1896 - 276 pages
...PB'xPA'=PC\ Therefore PB' xPA' ' = PBxPA. Ax. i Hence, if from a point without a circle two secants be drawn, the product of one secant and its external segment is equal to the product of the other and its external segment. 323. Exercise. — Prove § 322 by drawing A'B and AB' '. 324. Def. — The... | |
| Andrew Wheeler Phillips, Irving Fisher - Geometry - 1897 - 376 pages
...Therefore PB'x PA' = PBxPA. Ax. i Hence, if from a point without a circle two secants be drawn, thc product of one secant and its external segment is equal to the product of the other and its external segment. 311, Def. — The projection of a straight line AB, upon another straight... | |
| James Howard Gore - Geometry - 1898 - 232 pages
...28), PC 2 = PC' 2 , or PC=PC'. EXERCISES. 1. If -from a point without a circle two secants be drawn, the product of one secant and its external segment is equal to the product of the other and its external segment. 2. If from a point without a circle any number of secants are drawn, the... | |
| Webster Wells - Geometry - 1898 - 264 pages
...284. Cor. II. If any two secants be drawn through a fixed point without a circle, the product of one and its . external segment is equal to the product of the other and its external segment. To Prove AP x BP = A'P x B'P. (We have AP x BP and A'P x B'P each equal to... | |
| Webster Wells - Geometry - 1899 - 424 pages
...284. Cor. n. If any two secants be drawn through a fixed point without a circle, the product of one and its . external segment is equal to the product of the other and its external segment. To Prove AP x BP = A'P x B'P. (We have AP x BP and A'P x B'P each equal to... | |
| Webster Wells - Geometry - 1899 - 450 pages
...284. Cor. H. If any two secants be drawn through a fixed point without a circle, the product of one and its external segment is equal to the product of the other and its external segment. To Prove AP x BP = A'P x B'P. (We have AP x BP and A'P x B'P each equal to... | |
| Alan Sanders - Geometry, Modern - 1901 - 260 pages
...THEOREM 532. // from a point without a circle two secants be drawn terminating in the concave arc, the product of one secant and its external segment...product of the other secant and its external segment. Let AB and BC be two secants drawn from B to the circle whose center is O. To Prove AB • DB = CB... | |
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