 | American School (Chicago, Ill.) - Engineering - 1903 - 380 pages
...walls, etc. Example. — The loss through the walls and windows of a building is found to be 80000 BTU per hour in zero weather, what will be the size of furnace required to maintain an inside temperature of 70 degrees ? From the above we have the total... | |
 | American School (Chicago, Ill.) - Engineering - 1906 - 588 pages
...walls, etc. Example. — The loss through the walls and windows of a building is found to be 80000 BTU per hour in zero weather, what will be the size of furnace required to maintain an inside temperature of 70 degrees? From the above we hava Ihe total... | |
 | 1910 - 378 pages
...heating. First obtain the BTU required for ventilation, and to that add the heat loss through walls, etc., and divide the result by the efficiency of the heater under the given conditions. jx. 1 w' !, \\i Pipts Deep 4 6 3 10 12 14 16 18 20 5 IDS. 30 50 65 80 95 105 120 130 140 20 Ibs. 35... | |
 | American School of Correspondence, Chicago, Charles Lincoln Hubbard - Heating - 1908 - 252 pages
...conduction and leakage. Example. The loss through the walls and windows of a building is found to be 80,000 BTU per hour in zero weather. What will be the size of furnace required to maintain an inside temperature of 70 degrees? From the above, we have the total... | |
 | 1909 - 514 pages
...heating. First obtain the BTU required for ventilation, and to that add the heat loss through walls, etc.. and divide the result by the efficiency of the...hour. The heat loss through walls, etc., is 250,000 BT IVUWn UL 80 Ibs. Pipe Deep 5 Ibs. 20 Ibs. BU Ibs. 5 Ibs. 211 Ibs. 4 30 35 45 1600 1800 2000 6 50... | |
 | 1909 - 444 pages
...heating. First obtain the BTU required for ventilation, and to that add the heat loss through walls, etc.; and divide the result by the efficiency of the...air per hour. The heat loss through walls, etc., is 253,000 BTU per hour in zero weather. What will be the size of heater, and how many rows of pipe deep... | |
 | Charles Lincoln Hubbard - Heating - 1909 - 268 pages
...heating. First obtain the BTU required for ventilation, and to that add the heat loss through walls, etc., and divide the result by the efficiency of the heater under the given conditions. Example 2. — An audience hall is to be provided with 400,000 cu. ft. of air per hour. The heat loss through... | |
 | 1912 - 552 pages
...conduction and leakage. Example. The loss through the walls and windows of a building is found to be 80,000 BTU per hour in zero weather. What will be the size of furnace required to maintain an inside temperature of 70 degrees? From the above, we have the total... | |
 | Charles Lincoln Hubbard - Heating - 1914 - 328 pages
...heat required for ventilation, add to that the loss by transmission and leakage, and divide the sum by the efficiency of the heater under the given conditions. Example. — An auditorium is to be provided with 600,000 cu. ft. of air per hour. The heat lost by transmission and... | |
 | Heating - 1918 - 386 pages
...heating. First obtain the BTU required for ventilation, and to that add the heat loss through walls, etc.; and divide the result by the efficiency of the...must it be, with 20 pounds steam pressure? 400,000X70 nftn _ „ TT , ... = 509,090 BTU for ventilation. 55 Therefore 250,000 + 509,090 = 759,090 BTU,... | |
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The general method of computing the size of heater for any given building is the same as in the case of indirect heating. First obtain the BTU required for ventilation, and to that add the heat loss through walls, etc.; and divide the result by the efficiency... 
