 | Denison Olmsted - Astronomy - 1839 - 306 pages
...if A is the middle part, the opposite parts are a and B. Napier's rule is as follows : Radius into the sine of the middle part, equals the product of the tangents of the adjacent extremes, or of the cosines of the opposite extremes. (The corresponding vowels are marked to aid the... | |
 | Denison Olmsted - Astronomy - 1839 - 504 pages
...if A is the middle part, the opposite parts are a and B. Napier's rule is as follows : Radius into the sine of the middle part, equals the product of the tangents of the sdjaeent extremes, or of the cosines of the opposite extremes. (The corresponding vowels arc marked... | |
 | Denison Olmsted - Astronomy - 1839 - 304 pages
...the middle part, the opposite parts are a and B. Napier's rule is as follow* : Radius into the fine of the middle part, equals the product of the tangents of the adjacent extremes, or of the cosines of the opposite extremes. (The corresponding vowels are marked to aid the... | |
 | Anthony Dumond Stanley - Geometry - 1848 - 134 pages
...next to this and separated by it are called the adjacent parts, and the other two the opposite parts. The SINE of the MIDDLE part, equals the product of the TANGENTS of the ADJACENT parts, and equals the product of the COSINES of the OPPOSITE parts. This proposition may be more easily remembered,... | |
 | William Chauvenet - 1852 - 268 pages
...sides including it are regarded as adjacent. The rules are : I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. II. The sine of the middle part is equal to the product of the cosines of the opposite parts. The correctness of these rules will be... | |
 | William Somerville Orr - Science - 1854 - 534 pages
...then it will be found that all the formulas of the last article are included in the following rule. " The sine of the middle part equals the product of the tangents of the adjacent parts, and also equals the product of the cosines of the opposite parts ; " Or, Sin. mid. = tan. ad. = cos.... | |
 | George Roberts Perkins - Geometry - 1856 - 460 pages
...five parts is chosen as the middle part. NAPIER'S RULES, I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. II. The sine of the middle part is equal to the product of the cosines of the opposite parts. If now we take in turn each of the five... | |
 | George Roberts Perkins - Geometry - 1860 - 472 pages
...chosen as the middle part. 90°-B 90° -T NAPIER'S RULES. I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. II. The sine of the middle part is equal to the product of the cosines of the opposite parts. If now we take in turn each of the five... | |
 | John Daniel Runkle - Mathematics - 1860 - 590 pages
...spherical triangle being placed on the circumference of a circle, NAPIER'S Bules are as follows : — RULE I. The sine of the middle part equals the product of the cosines of the opposite parts, RULE II. The sine of the middle part is equal to the product of the... | |
 | Benjamin Greenleaf - Geometry - 1861 - 638 pages
...whatever be the middle part, we have as THE RULES OF NAPIER. I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. II. The sine of the middle part is equal to the product of tJie cosines of the opposite parts. 168. Napier's rules may be proved by... | |
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I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. II. The sine of the middle part is equal to the product of the cosines of the opposite parts. 
