Elements of GeometryHilliard and Metcalf, 1825 - 224 pages |
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Page 2
... whence we infer , that , Twice the less part is equal to the number to be divided diminished by the given excess ; and that , Once the less part is equal to half the difference between the num- ber to be divided and the given excess ...
... whence we infer , that , Twice the less part is equal to the number to be divided diminished by the given excess ; and that , Once the less part is equal to half the difference between the num- ber to be divided and the given excess ...
Page 3
... whence we conclude that or that and that lastly 2x = 9-5 , 2x = 4 , x = = 2 . By comparing now the import of these abridged expressions , which I have just given by means of the usual signs , with the process of simple reasoning , by ...
... whence we conclude that or that and that lastly 2x = 9-5 , 2x = 4 , x = = 2 . By comparing now the import of these abridged expressions , which I have just given by means of the usual signs , with the process of simple reasoning , by ...
Page 6
... whence , x + x + 40 + x +40 + 60 = 230 . If the given numbers be united in one expression and the un- known ones in another , x is found three times in the result , and for the sake of conciseness we write 3x + 140 230 . But since it is ...
... whence , x + x + 40 + x +40 + 60 = 230 . If the given numbers be united in one expression and the un- known ones in another , x is found three times in the result , and for the sake of conciseness we write 3x + 140 230 . But since it is ...
Page 7
... whence it follows that 3x230 140 , 3 x = 90 , 9 - x = = 30 . By adding to 30 the excess 40 of the middle part above the least , we have 70 for the middle part . By adding to 70 the excess 60 of the greatest above the mid- dle part , we ...
... whence it follows that 3x230 140 , 3 x = 90 , 9 - x = = 30 . By adding to 30 the excess 40 of the middle part above the least , we have 70 for the middle part . By adding to 70 the excess 60 of the greatest above the mid- dle part , we ...
Page 9
... Whence the least part , plus the least part , plus the excess of the middle one above the least , plus also the least part , Whence plus the excess of the middle > x + x + b + x + b + c = a . one above the least , plus the excess of the ...
... Whence the least part , plus the least part , plus the excess of the middle one above the least , plus also the least part , Whence plus the excess of the middle > x + x + b + x + b + c = a . one above the least , plus the excess of the ...
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Common terms and phrases
a² b³ algebraic Algebraic Quantities Arith arithmetic becomes binomial changing the signs coefficient common divisor consequently contains courier cube root decimal deduce denominator denoted divided dividend division employed entire number enunciation equa evident example exponent expression extract the root figures follows formula fraction given in art given number gives greater greatest common divisor last term letters logarithm manner method multiplicand multiplied negative number of arrangements observed obtain operation perfect square polynomials preceding article proposed equation proposed number quan question quotient radical quantities radical sign reduced remainder represented resolve result rule given second degree second member second term simple quantities square root subtract suppose taken tens third tion tities units unity unknown quantity vulgar fractions whence whole numbers
Popular passages
Page 9 - If two triangles have the three sides of the one equal to the three sides of the other, each to each, the triangles are congruent.
Page 44 - Divide the first term of the dividend by the first term of the divisor, and write the result as the first term of the quotient. Multiply the whole divisor by the first term of the quotient, and subtract the product from the dividend.
Page 63 - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. A D A' Hyp. In triangles ABC and A'B'C', To prove AABC A A'B'C' A'B' x A'C ' Proof. Draw the altitudes BD and B'D'.
Page 101 - Which proves that the square of a number composed of tens and units, contains the square of the tens plus twice the product of the tens by the units, plus the square of the units.
Page 8 - Any side of a triangle is less than the sum of the other two sides...
Page 122 - ... is negative in the second member, and greater than the square of half the coefficient of the first power of the unknown quantity, this equation can have only imaginary roots.
Page 180 - CD, &c., taken together, make up the perimeter of the prism's base : hence the sum of these rectangles, or the convex surface of the prism, is equal to the perimeter of its base multiplied by its altitude.
Page 54 - The sum of the squares on the sides of a parallelogram is equal to the sum of the squares on the diagonals.
Page 185 - The convex surface of a cone is equal to the circumference of the base multiplied by half the slant height.
Page 164 - If two triangles have two sides and the inchtded angle of the one respectively equal to two sides and the included angle of the other, the two triangles are equal in all respects.