Elements of GeometryHilliard and Metcalf, 1825 - 224 pages |
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Page viii
... square root of whole numbers Of numbers which are not perfect squares Method of determining whether the root found is too small To find the square and square root of a fraction Every prime number , which will divide the product of two ...
... square root of whole numbers Of numbers which are not perfect squares Method of determining whether the root found is too small To find the square and square root of a fraction Every prime number , which will divide the product of two ...
Page 99
... square root . I shall proceed , in the first place , to resolve this question , as it is involv- ed in the ... roots Equations of the Second Degree with one unknown Quantity . 99 Equations of the Second Degree having only one Unknown ...
... square root . I shall proceed , in the first place , to resolve this question , as it is involv- ed in the ... roots Equations of the Second Degree with one unknown Quantity . 99 Equations of the Second Degree having only one Unknown ...
Page 100
... square a number composed of three , 100. In order to resolve the sec- ond power of a number consisting of two figures , we must attend to the method by which it is formed ; for this purpose we must inquire ... square root of whole numbers.
... square a number composed of three , 100. In order to resolve the sec- ond power of a number consisting of two figures , we must attend to the method by which it is formed ; for this purpose we must inquire ... square root of whole numbers.
Page 101
... square of the units . This process may be exhibited thus ; 22,09 | 47 16 | 87 60,9 60 9 000 We write the proposed number in the manner of a dividend , and assign for the root the usual place of the divisor . We then separate the units ...
... square of the units . This process may be exhibited thus ; 22,09 | 47 16 | 87 60,9 60 9 000 We write the proposed number in the manner of a dividend , and assign for the root the usual place of the divisor . We then separate the units ...
Page 102
... root sought is 18 . By resolving the square of 18 into its three parts , we find a2 = 100 2 ab 160 b2 = 64 Total , 324 18 X 18 , and it may be seen , that the 6 tens , contained in the square of the units , being united to 160 , double ...
... root sought is 18 . By resolving the square of 18 into its three parts , we find a2 = 100 2 ab 160 b2 = 64 Total , 324 18 X 18 , and it may be seen , that the 6 tens , contained in the square of the units , being united to 160 , double ...
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Common terms and phrases
a² b³ algebraic Algebraic Quantities Arith arithmetic becomes binomial changing the signs coefficient common divisor consequently contains courier cube root decimal deduce denominator denoted divided dividend division employed entire number enunciation equa evident example exponent expression extract the root figures follows formula fraction given in art given number gives greater greatest common divisor last term letters logarithm manner method multiplicand multiplied negative number of arrangements observed obtain operation perfect square polynomials preceding article proposed equation proposed number quan question quotient radical quantities radical sign reduced remainder represented resolve result rule given second degree second member second term simple quantities square root subtract suppose taken tens third tion tities units unity unknown quantity vulgar fractions whence whole numbers
Popular passages
Page 9 - If two triangles have the three sides of the one equal to the three sides of the other, each to each, the triangles are congruent.
Page 44 - Divide the first term of the dividend by the first term of the divisor, and write the result as the first term of the quotient. Multiply the whole divisor by the first term of the quotient, and subtract the product from the dividend.
Page 63 - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. A D A' Hyp. In triangles ABC and A'B'C', To prove AABC A A'B'C' A'B' x A'C ' Proof. Draw the altitudes BD and B'D'.
Page 101 - Which proves that the square of a number composed of tens and units, contains the square of the tens plus twice the product of the tens by the units, plus the square of the units.
Page 8 - Any side of a triangle is less than the sum of the other two sides...
Page 122 - ... is negative in the second member, and greater than the square of half the coefficient of the first power of the unknown quantity, this equation can have only imaginary roots.
Page 180 - CD, &c., taken together, make up the perimeter of the prism's base : hence the sum of these rectangles, or the convex surface of the prism, is equal to the perimeter of its base multiplied by its altitude.
Page 54 - The sum of the squares on the sides of a parallelogram is equal to the sum of the squares on the diagonals.
Page 185 - The convex surface of a cone is equal to the circumference of the base multiplied by half the slant height.
Page 164 - If two triangles have two sides and the inchtded angle of the one respectively equal to two sides and the included angle of the other, the two triangles are equal in all respects.