Elements of GeometryHilliard and Metcalf, 1825 - 224 pages |
From inside the book
Results 1-5 of 74
Page vi
... Of Questions having two Unknown Quantities and of Negative Quantities Examples To resolve an equation , when the two members have the sign 55 · 56 58 59 60 - 61 A question in which one of the unknown quantities has vi Contents .
... Of Questions having two Unknown Quantities and of Negative Quantities Examples To resolve an equation , when the two members have the sign 55 · 56 58 59 60 - 61 A question in which one of the unknown quantities has vi Contents .
Page vii
... resolve equations of the first degree , when there are two un- known quantities 81 Of the Resolution of any given number of Equations of the First Degree , containing an equal number of Unknown Quantities General rule for deducing an ...
... resolve equations of the first degree , when there are two un- known quantities 81 Of the Resolution of any given number of Equations of the First Degree , containing an equal number of Unknown Quantities General rule for deducing an ...
Page viii
... resolving equations of the second degree , having only one unknown quantity Examples showing the properties of negative solutions In what cases problems of the second degree become absurd Expressions called imaginary An equation of the ...
... resolving equations of the second degree , having only one unknown quantity Examples showing the properties of negative solutions In what cases problems of the second degree become absurd Expressions called imaginary An equation of the ...
Page ix
... resolved in the same manner as those of the Second Degree To determine their several roots · ib . 167 · 157 158 160 162 am by x - a am = 0 , and the roots of unity · 163 Calculus of Radical Expressions 168 Process for performing on ...
... resolved in the same manner as those of the Second Degree To determine their several roots · ib . 167 · 157 158 160 162 am by x - a am = 0 , and the roots of unity · 163 Calculus of Radical Expressions 168 Process for performing on ...
Page xi
... resolve equations into factors of the second and higher de- grees Of the Resolution of Numerical Equations by Approximation Principle on which the method of finding roots by approxima- tion depends . Note on the changes of the value of ...
... resolve equations into factors of the second and higher de- grees Of the Resolution of Numerical Equations by Approximation Principle on which the method of finding roots by approxima- tion depends . Note on the changes of the value of ...
Contents
1 | |
2 | |
8 | |
14 | |
23 | |
30 | |
46 | |
53 | |
160 | |
168 | |
170 | |
174 | |
180 | |
186 | |
190 | |
192 | |
59 | |
66 | |
81 | |
91 | |
98 | |
99 | |
105 | |
111 | |
117 | |
123 | |
131 | |
136 | |
149 | |
150 | |
13 | |
27 | |
36 | |
8 | |
22 | |
44 | |
77 | |
86 | |
220 | |
Other editions - View all
Common terms and phrases
a² b³ algebraic Algebraic Quantities Arith arithmetic becomes binomial changing the signs coefficient common divisor consequently contains courier cube root decimal deduce denominator denoted divided dividend division employed entire number enunciation equa evident example exponent expression extract the root figures follows formula fraction given in art given number gives greater greatest common divisor last term letters logarithm manner method multiplicand multiplied negative number of arrangements observed obtain operation perfect square polynomials preceding article proposed equation proposed number quan question quotient radical quantities radical sign reduced remainder represented resolve result rule given second degree second member second term simple quantities square root subtract suppose taken tens third tion tities units unity unknown quantity vulgar fractions whence whole numbers
Popular passages
Page 9 - If two triangles have the three sides of the one equal to the three sides of the other, each to each, the triangles are congruent.
Page 44 - Divide the first term of the dividend by the first term of the divisor, and write the result as the first term of the quotient. Multiply the whole divisor by the first term of the quotient, and subtract the product from the dividend.
Page 63 - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. A D A' Hyp. In triangles ABC and A'B'C', To prove AABC A A'B'C' A'B' x A'C ' Proof. Draw the altitudes BD and B'D'.
Page 101 - Which proves that the square of a number composed of tens and units, contains the square of the tens plus twice the product of the tens by the units, plus the square of the units.
Page 8 - Any side of a triangle is less than the sum of the other two sides...
Page 122 - ... is negative in the second member, and greater than the square of half the coefficient of the first power of the unknown quantity, this equation can have only imaginary roots.
Page 180 - CD, &c., taken together, make up the perimeter of the prism's base : hence the sum of these rectangles, or the convex surface of the prism, is equal to the perimeter of its base multiplied by its altitude.
Page 54 - The sum of the squares on the sides of a parallelogram is equal to the sum of the squares on the diagonals.
Page 185 - The convex surface of a cone is equal to the circumference of the base multiplied by half the slant height.
Page 164 - If two triangles have two sides and the inchtded angle of the one respectively equal to two sides and the included angle of the other, the two triangles are equal in all respects.