Elements of GeometryHilliard and Metcalf, 1825 - 224 pages |
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Page ix
... obtain any power whatever of a simple quantity 136 137 ib . To extract the root of any power whatever of a simple quantity 138 To simplify radical expressions containing one term Of imaginary roots in general · 139 ib . Of fractional ...
... obtain any power whatever of a simple quantity 136 137 ib . To extract the root of any power whatever of a simple quantity 138 To simplify radical expressions containing one term Of imaginary roots in general · 139 ib . Of fractional ...
Page xi
... obtain the equation , the roots of which are the differ- ences between one of the roots of the proposed equation and ... obtained Inconvenience of this method when the roots differ but little 219 ib . 220 221 222 Note - respecting equal ...
... obtain the equation , the roots of which are the differ- ences between one of the roots of the proposed equation and ... obtained Inconvenience of this method when the roots differ but little 219 ib . 220 221 222 Note - respecting equal ...
Page 4
... obtain 2x , and that consequently 2x - a - b . a b We conclude then that half of 2 x or x == 2 2 This last result , being translated into ordinary language , by substituting the words and phrases denoted by the letters and signs which ...
... obtain 2x , and that consequently 2x - a - b . a b We conclude then that half of 2 x or x == 2 2 This last result , being translated into ordinary language , by substituting the words and phrases denoted by the letters and signs which ...
Page 12
... obtain this unknown quantity by itself in one member and all the known quantities in the other , is called resolving the equation . As the different questions , which are solved by algebra , lead to equations more or less compounded ...
... obtain this unknown quantity by itself in one member and all the known quantities in the other , is called resolving the equation . As the different questions , which are solved by algebra , lead to equations more or less compounded ...
Page 21
... obtain what the father was bound to pay the son , and 3 cents by the second , to find what the son engaged to return to the father . The first number ought to exceed the second by 28 cents , which the father owed the son . - We have for ...
... obtain what the father was bound to pay the son , and 3 cents by the second , to find what the son engaged to return to the father . The first number ought to exceed the second by 28 cents , which the father owed the son . - We have for ...
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Common terms and phrases
a² b³ algebraic Algebraic Quantities Arith arithmetic becomes binomial changing the signs coefficient common divisor consequently contains courier cube root decimal deduce denominator denoted divided dividend division employed entire number enunciation equa evident example exponent expression extract the root figures follows formula fraction given in art given number gives greater greatest common divisor last term letters logarithm manner method multiplicand multiplied negative number of arrangements observed obtain operation perfect square polynomials preceding article proposed equation proposed number quan question quotient radical quantities radical sign reduced remainder represented resolve result rule given second degree second member second term simple quantities square root subtract suppose taken tens third tion tities units unity unknown quantity vulgar fractions whence whole numbers
Popular passages
Page 9 - If two triangles have the three sides of the one equal to the three sides of the other, each to each, the triangles are congruent.
Page 44 - Divide the first term of the dividend by the first term of the divisor, and write the result as the first term of the quotient. Multiply the whole divisor by the first term of the quotient, and subtract the product from the dividend.
Page 63 - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. A D A' Hyp. In triangles ABC and A'B'C', To prove AABC A A'B'C' A'B' x A'C ' Proof. Draw the altitudes BD and B'D'.
Page 101 - Which proves that the square of a number composed of tens and units, contains the square of the tens plus twice the product of the tens by the units, plus the square of the units.
Page 8 - Any side of a triangle is less than the sum of the other two sides...
Page 122 - ... is negative in the second member, and greater than the square of half the coefficient of the first power of the unknown quantity, this equation can have only imaginary roots.
Page 180 - CD, &c., taken together, make up the perimeter of the prism's base : hence the sum of these rectangles, or the convex surface of the prism, is equal to the perimeter of its base multiplied by its altitude.
Page 54 - The sum of the squares on the sides of a parallelogram is equal to the sum of the squares on the diagonals.
Page 185 - The convex surface of a cone is equal to the circumference of the base multiplied by half the slant height.
Page 164 - If two triangles have two sides and the inchtded angle of the one respectively equal to two sides and the included angle of the other, the two triangles are equal in all respects.