| Charles Smith - Algebra - 1894 - 620 pages
...seen from the following example. Ex. 1. Solve the equations x2 + 3zf/ = 28, xy + 4 y2 = 8. Divide the members of the first equation by the corresponding members of the second equation ; we then have x* + 3xy _28_7 xy + 4 y* 8 2' Hence 2 (ж2 + 3 xy) = 7 (xy + 4 г/2) ; .-.... | |
| Silas Ellsworth Coleman - Arithmetic - 1897 - 178 pages
...circles; r^ and r, their radii. Then c, = 2 »*•„ c, = 2 x,v [Art. 97 (1)] Hence, dividing the members of the first equation by the corresponding members of the second, is equal to the ratio of their radii. Or, more briefly : The circumferences of two circles are to each... | |
| George Egbert Fisher - 1900 - 444 pages
...Multiplying the first fraction by b, and the second by d, we have vb = a, and wd = c. Dividing the members of the first equation by the corresponding members of the second, we have vb -=- wd = a -t- c, or — = — wd с Multiplying by j* ^x£ = 5x£ о wd b с b or *=^.... | |
| Macmillan & Co - Textbooks - 1901 - 804 pages
...second degree. The method will be seen from the following example. Ex. 1. Solve the equations Divide the members of the first equation by the corresponding members of the second equation ; we then have _ ¥ ~ 2 ' Hence 2 (*2 + 3xy) = 7 (xy + 4y2) ! that is, (2a; + 7y) (x - 4y)... | |
| George Egbert Fisher - 1901 - 622 pages
...Multiplying the first fraction by b, and the second by d, we have vb = a, and wd = c. Dividing the members of the first equation by the corresponding members of the second, we have , , vb a vb -a- wd = a -5- c, or — = — wd с Multiplying by £, l£x£ = SxjL о wd b с... | |
| Herbert Edwin Hawkes, William Arthur Luby, Frank Charles Touton - Algebra - 1919 - 536 pages
...a quadratic .has two sets of roots and hence cannot be equivalent to a linear system (see page 411, second paragraph). Sometimes an equation simpler than...possible, pair results, and check each set of real roots : a;2 -4^ = 20, i ' x + 2y = 2. 2 HINT. Division gives the equiv- R*h — 75 = 0, alent system *•... | |
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