 | A. Melrose (Teacher) - Arithmetic - 1795 - 140 pages
...left-hand period ; place its root in the quotient, and fubtraft the number itfelf from faid lefthand period ; and to the remainder annex the next period for a dividend. Write the* double of the part of the root found on the left-hand of the dividend, which divide by it,... | |
 | David Steel - 1805 - 392 pages
...the right hand of the given number, as in division. Subtract the square of this root from the first period ;and to the remainder, annex the next period, for a dividend. Double the root already found, and place it to the left hand of the dividend. Consider, what figure... | |
 | George G. Carey - Arithmetic - 1818 - 602 pages
...the quotient, as in Division, and place iU square under, and subtract 'A from, the above-mentioned period, and to the remainder annex the next period, for a dividend. Double the part of the root already found, and place it on the left of the dividend for a trial divisor,... | |
 | Roswell Chamberlain Smith - Arithmetic - 1827 - 216 pages
...•put the root in the quotient, and bring down the next period, to the right hand of the remainder for a dividend. Multiply the square of the root by 300 for a divisor. I'ind how many times this divisor is contained in the dividend, and put the answer in the quotient:... | |
 | William Smyth - Algebra - 1830 - 278 pages
...of a quotient. Subtract the power from the period. To the remainder bring down the first figure of the next period for a dividend. Multiply the square of the root already found by three to form a divisor. See how many times the divisor is contained in the dividend,... | |
 | Silas Totten - Algebra - 1836 - 320 pages
...quotient in division. Subtract its cube from the aforementioned period, and to the remainder bring down the next period for a dividend. Multiply the square of the root already found by 300, for a divisor. Seek how often the divisor is contained in the dividend, and place... | |
 | James Thomson (LL.D.) - Arithmetic - 1837 - 296 pages
...contained in it, if it be not a cute tUelf. (3.) Subtract the third power of this figure from the first period, and to the remainder annex the next period for a dividend, and for part of the divisor take 300 times the square of the part of the root already obtained. ^.)... | |
 | James W. Kavanagh - 1846 - 304 pages
...period, enter it under the period, and its root in the quotient place, tahe this 3rd power from the period, and to the remainder annex the next period for a dividend. III. Divide this dividend, omitting the last two figures, by three times the 2nd power of the figure... | |
 | John Fair Stoddard - Arithmetic - 1852 - 320 pages
...e-rceed t/it left-hand period, and place it on the right in the form of a quotient ; then subtract its cube from that period and. to the remainder annex the next period for t/te FIRST DIVIDEND. Annex a cipher to the r-oot found and multiply its square by 3 for a TRIAL DIVISOR,... | |
 | Mathew Wilson - 1854 - 210 pages
...that on the left, and place its root on the right. 3. Subtract this square number from the highest period, and to the remainder annex the next period for a dividend. 4. Double the figure of the root found for a divisor ; find how often it is contained in the dividend,... | |
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Subtract the square of this figure from the left-hand period, and to the remainder annex the next period for a dividend. 
