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To find the area of a trapezoid. RULE. Multiply half the sum of the two parallel sides by the perpendicular distance between them : the product will be the area.
The complete measurer: or, The whole art of measuring, containing the ... - Page 37
by Thomas Keith - 1817

## Mathematics: Compiled from the Best Authors and Intended to be the ..., Volume 2

Mathematics - 1801
...street. • t Ans. 76- 1 2333 35 feet. PROBLEM IV. 7o f:nd tlie area of a trapezoid. • RULE.* Multiply the sum of the two parallel sides by the perpendicular distance between them, and half the product will be the area. • EXAMPLES. * DEMONSTRATION. or (because B»=DE) =-, .-. A ABD+...

## A System of Geometry and Trigonometry: Together with a Treatise on Surveying ...

Abel Flint - Geometry - 1804 - 216 pages
...Angle 28° 5'. 0.47076 105X85=8925, and 8925X0.47076=4201 the double Area of the Triangle. PROBLEM X. To find the Area of a Trapezoid. RULE. Multiply half...Sides by the perpendicular distance between them, or the Sum of the two parallel Sides by half the perpendicular distance ; the Product will be the Area....

## A System of Geometry and Trigonometry: Together with a Treatise on Surveying ...

Abel Flint - Geometry - 1808 - 192 pages
...28* 5'. 0.47076 105x85=8925, and 8925x0.47076=4201 the double Area of the Triangle. • PROBLEM X. To find the Area of a Trapezoid. RULE. Multiply half...Sides by the perpendicular distance between them, or the sum of the two parallel Sides by half the perpendicular distance ; the Product will be the Area....

## The principles of architecture, Volume 1

Peter Nicholson - 1809 - 426 pages
...42 504=the area of ABCD. PROBLEM VI. To find the area of a trapezoid. Multiply the half sum of the parallel sides by the perpendicular distance between them, and the product will be the area. EXAMPLE I. What is fhe area of a board or plank in the form of a trapeziod, being 1f. 7i. one end, 2f. 3i....

## A SYSTEM OF GEOMETRY AND TRIGONOMETRY

Abel Flint - Surveying - 1813 - 168 pages
...and 8925X0.47076=4201 the double Area of the Triangle. PROBLEM X. To find the Area of a Trapezovl. RULE. Multiply half the Sum of the two parallel Sides by the perpendicular distance between them, or the sum of the two parallel Sides by half the perpendicular distance; the Product will be the Area....

## The new practical gager

Matthew Iley - 1820 - 512 pages
...Quadrilateral wherein two unequal Sides are Parallel to one another. RULE. Multiply half the sum of the parallel sides by the perpendicular distance between them, and the product will be the area. Let ABCD be a quadrilateral, wherein AC and BD are parallel but unequal; and let EF, the perpendicular...

## A Treatise on Practical Gauging

Anthony Nesbit, W. Little - Measurement - 1822 - 916 pages
...Ant. 97.3383 bushels. PROBLEM VII. To Jind the area of a trapezoid. RULE. • By the Pen. Multiply the sum of the two parallel sides by the perpendicular distance between them, and half the product will be the area in square inches. Divide this area by 2 82, 231, and 2150.42, and...

## A System of Geometry and Trigonometry: Together with a Treatise on Surveying ...

Abel Flint - Geometry - 1825 - 252 pages
...and 8925 X 0.47076=4201 tbe double Area of the Triangle. PROBLEM X. To find the Jbeaof a TrapezoiA. RULE. Multiply half the Sum of the two parallel Sides by the perpendicular distance between them, or the sum of the two parallel Sides by half the perpendicular distance, the product will be the Area....