| Charles Vyse - Arithmetic - 1785 - 325 pages
...1 . Multiply Half the the Circumference by Half the Diameter, and the Product will be the Area. Or, **2. Multiply the Square of the Diameter by ,78,54, and' the Product will be the Area.** Or, • 3. Multiply the Square of the Circumference by ,079574, and the Product will be the Area. Or,... | |
| Charles Hutton - Measurement - 1788 - 728 pages
...the area CAE of the whole circle or feftor accordingly. ^_. £. D. * RULE II. « Multiply the fquare **of the diameter by '7854, and the product will be the area*** EXAMPLES. i, What is the area of a circle whofe diameter is I, and circumference 3'i4i6? Vl4-l6 XI... | |
| Charles Vyse - Arithmetic - 1806 - 342 pages
...RULES. 1. Multiply Half the Circumference by Half the Diameter, and tin- Product will 1& the Area. Or, **2. Multiply the Square of the Diameter by ,7854, and the Product will be the Area.** Or, 3. Multiply the Square of the Circumference by ,079574, and the Product will be the Area. Or, 4.... | |
| Nathan Daboll - Arithmetic - 1815 - 240 pages
...circumference^ and the product is the area ; or if the diameter is given without the circumference, **multiply the square of the diameter by ,7854 and the product will be the area.** EXAMPLE8. 1. Required the area of a circle whose diameter 'is 12 inches, and circumference 37,7 inches.... | |
| Nathan Daboll - Arithmetic - 1818 - 240 pages
...circumference, and the product is the area ; or if the diameter is given • •without the circumference, **multiply the square of the diameter by ,7854 and the product will be- the area.** EXAMPLES. 1. Required the area of a circle whose diameter is 12 inches, and circumference 37,7 inches.... | |
| William Hawney - Geometry - 1820 - 312 pages
...circumference by half the diameter : Or take -J of the product of the whole circumference and diameter,.and **it will give the area. 2. Multiply the square of the...area. 3. As 452 is to 355, so is the square of the** diameter to the area. 4. As 14 is to 11, so is the square of the diameter to the area. 5. Multiply... | |
| William Jillard Hort - 1822 - 308 pages
...Rule 1. Multiply half the circumference by half the diameter, and the product will be the area. Rule **2. Multiply the square of the diameter by 7854', and the product will be the area.** ProUem. To find the area of an ellipse. Multiply the product of the two axes, by the number 7854. for... | |
| Nicolas Pike - Arithmetic - 1822 - 560 pages
...1 5. The Diameter being given to find the Area of a Circle without finding the Circumference. RULE. **Multiply the square of the diameter by -7854,* and the product will be the area** of the circle, whose diameter was given. EXAMP. The diameter of a circle being 12, to find the area... | |
| James Mitchell - Mathematics - 1823 - 576 pages
...Diameter being given. 1. Multiply the diameter by 3-14159, and the product will be the circumference. **2. Multiply the square of the diameter by -7854, and the product •will be the area.** Or general, if we put diameter = D, circumference = C, area — A, and 3-141S9 = 1', we have the following... | |
| Anthony Nesbit - Surveying - 1824 - 476 pages
...area. Or, divide the product of the whole circumference and diameter by 4t9 and the quotient will be **the area. 2. Multiply the square of the diameter by .7854, and** tlie product will be the area. 3. Multiply the square of the circumference by .07958, and the product... | |
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