## Elements of Geometry and Trigonometry |

### From inside the book

Page 41

... and is formed by two chords . B an arc . The chord , or subtense of an arc , is the straight line FG , which joins its two extremities . † 4. A

... and is formed by two chords . B an arc . The chord , or subtense of an arc , is the straight line FG , which joins its two extremities . † 4. A

**segment**is the surface or portion of a circle , included between an arc and its chord . Page 55

All the angles BAC , BDC , BEC , inscribed in the same

All the angles BAC , BDC , BEC , inscribed in the same

**segment**are equal ; because they are all measured by the half of the same arc BOC . B Cor . 2. Every angle BAD , inscribed in a semicircle is a right angle ; because it is measured ... Page 65

A On a given straight line to describe a

A On a given straight line to describe a

**segment**that shall contain a given angle ; that is to say , a**segment**such , that all the angles inscribed in it , shall be equal to the given angle . Let AB be the given straight line , and C ... Page 66

If the given angle were a right angle , the required

If the given angle were a right angle , the required

**segment**would be a semicircle , described on AB as a diameter . PROBLEM XVII . To find the numerical ratio of two given straight lines , these lines being supposed to have a common ... Page 68

In two different circles , similar arcs , sectors , or

In two different circles , similar arcs , sectors , or

**segments**, are those which correspond to equal angles at the centre . ... the sector BAC to the sector DOE , and the**segment**whose chord is BC , to the seg ment whose chord is DE .### What people are saying - Write a review

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### Common terms and phrases

ABCD adjacent altitude base become Book called centre chord circle circumference circumscribed common cone consequently contained Cosine Cotang cylinder described determine diameter difference distance divided draw drawn equal equations equivalent expressed extremities faces feet figure follows formed four frustum give given gles greater half hence homologous hypothenuse included inscribed intersection less let fall logarithm manner means measured meet middle multiplied number of sides opposite parallel parallelogram pass perpendicular plane polygon prism PROBLEM Prop proportional PROPOSITION pyramid quadrant quantities radii radius ratio reason rectangle regular remaining right angles Scholium segment sides similar Sine solid solid angle sphere spherical triangle square straight line suppose taken Tang tangent THEOREM third triangle triangle ABC unit vertex whole