Elements of Geometry and Trigonometry |
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Page 12
A theorem is a truth , which becomes evident by means of a train of reasoning called a demonstration . A problem is a question proposed , which requires a solution . A lemma is a subsidiary truth , employed for the demonstration of a ...
A theorem is a truth , which becomes evident by means of a train of reasoning called a demonstration . A problem is a question proposed , which requires a solution . A lemma is a subsidiary truth , employed for the demonstration of a ...
Page 14
PROPOSITION I. THEOREM . If one straight line meet another straight line , the sum of the two adjacent angles will be equal to two right angles . E Let the straight line DC meet the straight line AB at C , then will the angle ACD + the ...
PROPOSITION I. THEOREM . If one straight line meet another straight line , the sum of the two adjacent angles will be equal to two right angles . E Let the straight line DC meet the straight line AB at C , then will the angle ACD + the ...
Page 15
THEOREM . If a straight line meet two other straight lines at a common point , making the sum of the two adjacent angles equal to two right angles , the two straight lines which are met , will form one and the same straight line .
THEOREM . If a straight line meet two other straight lines at a common point , making the sum of the two adjacent angles equal to two right angles , the two straight lines which are met , will form one and the same straight line .
Page 17
THEOREM . If two triangles have two angles and the included side of the one , equal to two angles and the included side of the other , each to each , the two triangles will be equal . D Let the angle E be equal to the angle B ...
THEOREM . If two triangles have two angles and the included side of the one , equal to two angles and the included side of the other , each to each , the two triangles will be equal . D Let the angle E be equal to the angle B ...
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Common terms and phrases
ABCD adjacent altitude base become Book called centre chord circle circumference circumscribed common cone consequently contained Cosine Cotang cylinder described determine diameter difference distance divided draw drawn equal equations equivalent expressed extremities faces feet figure follows formed four frustum give given gles greater half hence homologous hypothenuse included inscribed intersection less let fall logarithm manner means measured meet middle multiplied number of sides opposite parallel parallelogram pass perpendicular plane polygon prism PROBLEM Prop proportional PROPOSITION pyramid quadrant quantities radii radius ratio reason rectangle regular remaining right angles Scholium segment sides similar Sine solid solid angle sphere spherical triangle square straight line suppose taken Tang tangent THEOREM third triangle triangle ABC unit vertex whole