Elements of Geometry and Trigonometry |
From inside the book
Results 1-5 of 33
Page 11
The side opposite the right angle is called the hypothenuse . Thus , in the triangle ABC , right - angled at A , the side BC is the hypothenuse . B 17. Among the quadrilaterals , we distinguish : The square , which has its sides equal ...
The side opposite the right angle is called the hypothenuse . Thus , in the triangle ABC , right - angled at A , the side BC is the hypothenuse . B 17. Among the quadrilaterals , we distinguish : The square , which has its sides equal ...
Page 24
If a straight line have two points D and F , equally distant from the extremities A and B , it will be perpendicular to AB at the middle point C. PROPOSITION XVII . THEOREM . If two right angled triangles have the hypothenuse and a side ...
If a straight line have two points D and F , equally distant from the extremities A and B , it will be perpendicular to AB at the middle point C. PROPOSITION XVII . THEOREM . If two right angled triangles have the hypothenuse and a side ...
Page 47
M D A In the right angled triangles CAF , DCG , the hypothenuses CA , CD , are equal ; and the side AF , the half of AB , is equal to the side DG , the half of DE : hence the triangles are equal , and CF is equal to CG ( Book I. Prop .
M D A In the right angled triangles CAF , DCG , the hypothenuses CA , CD , are equal ; and the side AF , the half of AB , is equal to the side DG , the half of DE : hence the triangles are equal , and CF is equal to CG ( Book I. Prop .
Page 64
... be always two equal tangents AB , AD , passing through the point A : they are equal , because the right angled triangles CBA , CDA , have the hypothenuse CA common , and the side CB = CD ; hence they are equal ( Book I. Prop .
... be always two equal tangents AB , AD , passing through the point A : they are equal , because the right angled triangles CBA , CDA , have the hypothenuse CA common , and the side CB = CD ; hence they are equal ( Book I. Prop .
Page 77
Scholium . This proposition is equivalent to the algebraical formula , ( a + b ) x ( a — b ) = a2 — b2 . PROPOSITION XI . THEOREM The square described on the hypothenuse BOOK IV . 2.7.
Scholium . This proposition is equivalent to the algebraical formula , ( a + b ) x ( a — b ) = a2 — b2 . PROPOSITION XI . THEOREM The square described on the hypothenuse BOOK IV . 2.7.
What people are saying - Write a review
We haven't found any reviews in the usual places.
Other editions - View all
Common terms and phrases
ABCD adjacent altitude base become Book called centre chord circle circumference circumscribed common cone consequently contained Cosine Cotang cylinder described determine diameter difference distance divided draw drawn equal equations equivalent expressed extremities faces feet figure follows formed four frustum give given gles greater half hence homologous hypothenuse included inscribed intersection less let fall logarithm manner means measured meet middle multiplied number of sides opposite parallel parallelogram pass perpendicular plane polygon prism PROBLEM Prop proportional PROPOSITION pyramid quadrant quantities radii radius ratio reason rectangle regular remaining right angles Scholium segment sides similar Sine solid solid angle sphere spherical triangle square straight line suppose taken Tang tangent THEOREM third triangle triangle ABC unit vertex whole
Bibliographic information
| Title | Elements of Geometry and Trigonometry DAVIES' COURSE OF MATHEMATICS |
| Author | Adrien Marie Legendre |
| Editor | Charles Davies |
| Translated by | David Brewster |
| Publisher | A.S. Barnes and Company, 1839 |
| Original from | Harvard University |
| Digitized | 14 Jan 2008 |
| Length | 359 pages |
| Export Citation | BiBTeX EndNote RefMan |