Elements of Geometry and Trigonometry |
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Page 27
... manner it may be proved that OGA + GOC is equal to two right angles . Cor . 1. If OGB is a right angle , GOD will be a right angle also therefore , every straight line perpendicular to one of two parallels , is perpendicular to the ...
... manner it may be proved that OGA + GOC is equal to two right angles . Cor . 1. If OGB is a right angle , GOD will be a right angle also therefore , every straight line perpendicular to one of two parallels , is perpendicular to the ...
Page 88
... manner AI : AF :: IK : FG ; hence , the ratio AI : AF being common , we shall have DI : BF :: IK : FG . In the same manner we shall find IK FG KL : GH ; and so with the other segments : hence the line DE is divided at the points I , K ...
... manner AI : AF :: IK : FG ; hence , the ratio AI : AF being common , we shall have DI : BF :: IK : FG . In the same manner we shall find IK FG KL : GH ; and so with the other segments : hence the line DE is divided at the points I , K ...
Page 140
... manner , it may be shown , that SC = TF , and BC = EF . That granted , the quadrilateral SAOC is equal to the quadri- lateral TDPF : for , place the angle ASC upon its equal DTF ; because SA = TD , and SC = TF , the point A will fall on ...
... manner , it may be shown , that SC = TF , and BC = EF . That granted , the quadrilateral SAOC is equal to the quadri- lateral TDPF : for , place the angle ASC upon its equal DTF ; because SA = TD , and SC = TF , the point A will fall on ...
Contents
BOOK | 7 |
Problems relating to the First and Third Books 57 | 57 |
BOOK IV | 68 |
14 other sections not shown
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Common terms and phrases
adjacent adjacent angles altitude angle ACB angle BAC ar.-comp base multiplied bisect Book VII centre chord circ circumference circumscribed common cone consequently convex surface cosine Cotang cylinder diagonal diameter dicular distance divided draw drawn equally distant equations equivalent feet figure find the area formed four right angles frustum given angle given line gles greater homologous sides hypothenuse inscribed circle inscribed polygon intersection less Let ABC number of sides opposite parallelogram parallelopipedon pendicular perimeter perpen perpendicular plane MN polyedron polygon ABCDE PROBLEM Prop proportional PROPOSITION pyramid quadrant quadrilateral quantities radii radius ratio rectangle regular polygon right angled triangle S-ABC Scholium secant segment similar sine slant height solid angle solid described sphere spherical polygon spherical triangle square described straight line TABLE OF LOGARITHMIC tang tangent THEOREM triangle ABC triangular prism vertex