The product of two binomials having a common term equals the square of the common term plus the product of the common term by the sum of the other terms, plus the product of the other terms. A First Course in Algebra - Page 100by Frederick Charles Kent - 1913 - 249 pagesFull view - About this book
| Edward Brooks - Algebra - 1888 - 190 pages
...(a™ -6"). . Ans. a?m - b2". 9. Expand (a2™ + 63")(a2"> — 63"). ^Ins. a4™ — 6**. THEOREM IV. The product of two binomials having a common term equals the square of the common term, plus the algebraic sum of the other two terms into the common term, and the product of the unlike terms. OPERATION.... | |
| David Martin Sensenig - Algebra - 1889 - 388 pages
...like term ; and the third term is the algebraic product of the unlike terms. Therefore, Prin. 40. — The product of two binomials having a common term equals the square of the common term, and the algebraic sum of the unlike terms times the common term, and the algebraic product of the unlike... | |
| David Martin Sensenig - Algebra - 1890 - 556 pages
...algebraic product of the unlike terms (+ ax + 6), (ox — S), (— о x — Ъ). Therefore, Prin. 2. — The product of two binomials having a common term equals the square of the common term and the algebraic sum of the unlike terms into the common term, and the algebraic product of the unlike... | |
| Scoby McCurdy - Algebra - 1907 - 264 pages
...14. ж8 — ж-2. . Page 14, § 47. 1. The product of two binomials having a common term is equal to the square of the common term, plus the product of the common term and the sum of the second terms, plus the product oj the second terms. 2. x2 + (a + b) x +ab. 3. ж2 + 5 ж... | |
| Matthew Scoby McCurdy - 1894 - 240 pages
...14. ж8 — ж-2. Page 14, § 47. 1. The product of two binomials having a common term, is equal to the square of the common term, plus the product of the common term and (he sum of the second terms, plus the product of the second lerms. 2. ж2 + (« + b) x + ab. 3. ж2... | |
| George Washington Hull - Algebra - 1895 - 358 pages
...9. (a - Sx) (a + 8ж). 19. (a"2 - 6™2) (a"2 + 6"2). 10. (3z - 7) (Зж + 7). 20. ( PRINCIPLE IV. The product of two binomials having a common term equals the square of the common term, plus the algebraic sum of the other two terms into the common term, and the product of the unlike terms. Thus,... | |
| George Edward Atwood - 1900 - 276 pages
...The first term of each product is the square of the common term. The second term of each product is the product of the common term and the algebraic sum of the second terms. The third term of each product is the product of the second terms. When the signs of... | |
| Edward Brooks - Algebra - 1901 - 248 pages
...+ 6n) (a" -?'"). 14. (a'na;'ri) (a'--ta;'") 15. (a'-'-c"*1) (a"-' 16. an + nc" + na"' + THEOREM IV. The product of two binomials having a common term equals the square of tlie common term, plus tlie algebraic sum of the other two terms into the common tern, and tlie product... | |
| George Edward Atwood - Arithmetic - 1902 - 168 pages
...^ - 7 a; - 18. The first term of each product is the square of the common term. The second term is the product of the common term and the algebraic sum of the second terms. The third term is the product of the second terms. ORAL EXERCISES ). 2. (a; 3. O + 4)O... | |
| John William Hopkins - 1904 - 276 pages
...x + 24 ж2 + 11 x + 24 Multiply (x - 8) by (x - 3). ж - 8 x - 3 ж2- 8ж - Зж + 24 ^ - 11 x + 24 The product of two binomials having a common term equals the square of the common term, the algebraic sum of the other two terms into the common term, and the product of the other two terms.... | |
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