A Course of Mathematics: Composed for the Use of the Royal Military Academy |
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Page 5
... becomes ten times as many . For every C and Ɔ , placed one at each end , it becomes ten times as much . A bar over any number , increases it 1000 fold . 1000000 = M or CCCCI9300 . 2000000 & C . MM . & c . EXPLANATION OF CERTAIN ...
... becomes ten times as many . For every C and Ɔ , placed one at each end , it becomes ten times as much . A bar over any number , increases it 1000 fold . 1000000 = M or CCCCI9300 . 2000000 & C . MM . & c . EXPLANATION OF CERTAIN ...
Page 7
... becomes 4000 + 690 + 50 + 8. But 40004 X 1000 = 4 × ( 999 + 1 ) = 4 × 999 +4 . In like manner 6006 X 996 ; and 50 5 x 9 +5 . Therefore the given number 46584 × 999 + 4 + 6 × 99 + 6 + 5X9 + 5 + 8 = 4 × 999 + 6 × 99 +5 × 9 + 4 + 6 + 5 + 8 ...
... becomes 4000 + 690 + 50 + 8. But 40004 X 1000 = 4 × ( 999 + 1 ) = 4 × 999 +4 . In like manner 6006 X 996 ; and 50 5 x 9 +5 . Therefore the given number 46584 × 999 + 4 + 6 × 99 + 6 + 5X9 + 5 + 8 = 4 × 999 + 6 × 99 +5 × 9 + 4 + 6 + 5 + 8 ...
Page 79
... positive , and the other negative , then the theorem becomes & = errors are unlike . rb + sa , which is the rule in this case , or when the r + s EXAMPLE . 1. What number is that , which being POSITION . 79 19 Double Position.
... positive , and the other negative , then the theorem becomes & = errors are unlike . rb + sa , which is the rule in this case , or when the r + s EXAMPLE . 1. What number is that , which being POSITION . 79 19 Double Position.
Page 160
... become , by ( Art . 88 ) √91 = 7 91 the root of or 13 ' will be ( 13 ) 9.53 13 1 or a result within of the true ... becomes 23 X 3 ( 4 ) 2 × ( 3 ) 2 or and the denominator is thus made a perfect square . Extracting the 69 ( 12 ) i 1 ...
... become , by ( Art . 88 ) √91 = 7 91 the root of or 13 ' will be ( 13 ) 9.53 13 1 or a result within of the true ... becomes 23 X 3 ( 4 ) 2 × ( 3 ) 2 or and the denominator is thus made a perfect square . Extracting the 69 ( 12 ) i 1 ...
Page 177
... becomes ( 5c2 ) + 4 ( 5c2 ) 3 × ( 2yz ) 1.2 X a = 2yz n = 4 nxn - la ......... n ( n — 1 ) itn - e a2 4.3 www 1.2 n ( n − 1 ) ( n — 2 ) 1.2.3 xn - 3a3 n ( n - 1 ) ( n - 2 ) ( n - 3 ) n - 4a4 www 1.2.3.4 ( 5 c2 — 2 yz ) 1 = 625 c3 — www ...
... becomes ( 5c2 ) + 4 ( 5c2 ) 3 × ( 2yz ) 1.2 X a = 2yz n = 4 nxn - la ......... n ( n — 1 ) itn - e a2 4.3 www 1.2 n ( n − 1 ) ( n — 2 ) 1.2.3 xn - 3a3 n ( n - 1 ) ( n - 2 ) ( n - 3 ) n - 4a4 www 1.2.3.4 ( 5 c2 — 2 yz ) 1 = 625 c3 — www ...
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axis become x becomes bisected called centre chord circle circumference co-ordinates Corol cosec cosine curve decimal denominator determine diameter difference differential co-efficient distance Divide divisor draw dx dy dy dx equal EXAMPLES expression feet figure formula fraction function greatest common measure Hence hyperbola inches latus rectum least common multiple logarithm manner monomial multiplied negative nth root opposite P₁ parallel parallelogram perpendicular polynomial positive Prob problem Prop proportional quotient radius ratio rectangle remaining right angles rule sides sine square root straight line Substituting subtract tangent Taylor's theorem THEOREM triangle ABC unknown quantity whence whole number yards