| Frederick Emerson - Arithmetic - 1834 - 300 pages
...remainder may be expressed by two factors; thus, (10X10X3 + 10X3X5 + 5X5) 5: therefore, if we divide by three times the square of the first term of the root, plus three times the first term multiplied by the second term, plus the square of the second term,... | |
| James Bryce - Algebra - 1837 - 322 pages
...cube root of the first term, and subtract its cube from the given quantity; 3* take the quotient of the first term of the remainder by three times the square of the part of the root already found, and set it down as the next term of the root: then, to the treble of... | |
| Algebra - 1838 - 372 pages
...the two first terms of R,form the cube of the binomial and subtract it from N ; after which, divide the first term of the remainder by three times the 'square of the first term of R : the quotient will be the third term of R. IV. Cube the three terms of the root found, and subtract... | |
| Bourdon (M., Louis Pierre Marie) - Algebra - 1839 - 368 pages
...first terms of R,form the cube of the trinomial and subtract it from N ; after which, divide the fast term of the remainder by three times the square of the first term of R : the quotient will Ic the third term of R. IV. Cube the three terms of the root found, and subtract... | |
| Frederick Emerson - Arithmetic - 1839 - 300 pages
...remainder may be expressed by two factors; thus, (10X10X3 + 10X3X5- 1-5x1) 5: therefore, if we divide by three times the square of the first term of the root, plus three times the first term multiplied by the second term, plus the square of the second term,... | |
| Charles Davies - Algebra - 1845 - 382 pages
...the first two terms of R, form the cube of this binomial and subtract it from N ; after which, divide the first term of the remainder by three times the square of the first term of R : the quotient will be the third term of R. IV. Cube the three terms of the root found, and subtract... | |
| Ormsby MacKnight Mitchel - Algebra - 1845 - 308 pages
...root, cube the root already found, subtract it from the power, and bring down the remainder ; divide the first term of the remainder by three times the square of the root already found, and the quotient will be the second term of the root. To get the third term of... | |
| Elias Loomis - Algebra - 1846 - 380 pages
...letter, take the cube root of the first term, and subtract the cube from the given quantity. Divide the first term of the remainder by three times the square of the root already found, the quotient will be the second term of the root. Complete the divisor by adding... | |
| Elias Loomis - Algebra - 1846 - 376 pages
...letter, take the cube root of the first term, and subtract the cube from the given quantity. Divide the first term of the remainder by three times the square of the root already found, the quotient will be the second term of the root. Complele the divisor by adding... | |
| Algebra - 1847 - 386 pages
...the. ßrst two terms of R, form the cube of this binomial and subtract il from N ; after which, divide the first term of the remainder by three times the square of the ßrst term of R : the quotient will be the third term of R. IV. Cube the three terms of the root found,... | |
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