 | Ormsby MacKnight Mitchel - Algebra - 1845 - 308 pages
...and place the quotient in the quotient, as its first term. Multiply every term of the divisor by the first term of the quotient, and subtract the product from the dividend, and oring down the remainder. Divide the first term of the remainder by the first term of the divisor,... | |
 | Elias Loomis - Algebra - 1846 - 376 pages
...the divisor, the result will be thefirst term of the quotient. 3. Multiply the divisor by this term, and subtract the product from the dividend. 4. Divide the first term of the remainder by t he first term of the divisor, the result will be the second term of the quotient. 5. Multiply the... | |
 | John William Colenso (bp. of Natal.) - 1848 - 238 pages
...by that of the divisor, and set the result in the quotient ; (iii) Multiply the whole divisor by the first term of the quotient, and subtract the product from the dividend ; Ex. 1. Ex. 2. l -а;) 1-%х + х* (1-х Зж-4у) 6ж3-17ж!у + 16у3 (2Ж11 - Зжу - 4у* 1-... | |
 | William Smyth - Algebra - 1851 - 272 pages
...term of the divisor, and set the result, with its proper sign, as the first term of the quotient. 2°. Multiply the divisor by this first term of the quotient and subtract the product from the dividend. 3°. Divide the first term of the remainder by the first term of the divisor, place the result in the... | |
 | Elias Loomis - Algebra - 1855 - 356 pages
...the divisor, the result will be the first term of the quotient. 3. Multiply the divisor by this term, and subtract the product from the dividend. 4. Divide...the first term of the remainder by the first term oj the divisor, the result will be the second term of the quotient. 5. Multiply the divisor by this... | |
 | John Robertson (LL.D., of Upton Park sch.) - 1861 - 140 pages
...that of the divisor, and set the result in the quotient ; (iii.) Multiply the whole divisor by the first term of the quotient, and subtract the product from the dividend ; (iv.) Bring down fresh terms (as may be required) from the dividend, and repeat the whole operation.... | |
 | Charles Scott Venable - Algebra - 1880 - 168 pages
...the first term of the divisor, for the first term of the quotient. Then multiply the divisor by the first term of the quotient, and subtract the product from the dividend. Divide the first term of the remainder by the first term of the divisor, and proceed as before, continuing... | |
 | Charles Scott Venable - 1890 - 170 pages
...the first term of the divisor, for the first term of the quotient. Then multiply the divisor by the first term of the quotient, and subtract the product from the dividend. Divide lhe first term of the remainder by the first term of the divisor, and proceed as before, continuing... | |
 | James Morford Taylor - Algebra - 1893 - 362 pages
...term of the divisor: the result will be the first term, of the quotient. Multiply the divisor by the first term of the quotient; and subtract the product from the dividend. Treat the remainder, if any, as a new dividend, and so on. EXAMPLE 1. Divide 3 a3 - 4 a2 + 2 a - 1... | |
 | Emerson Elbridge White - Algebra - 1896 - 418 pages
...and write the result as the first term of the quotient. Multiply all the terms of the divisor by the first term of the quotient, and subtract the product from the dividend. If there be a remainder, consider it as a new dividend, divide its first term by the first term of... | |
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Divide the first term of the dividend by the first term of the divisor, and write the result as the first term of the quotient. Multiply the whole divisor by the first term of the quotient, and subtract the product from the dividend. 
