 | Pliny Earle Chase - Arithmetic - 1844 - 246 pages
...found, by the last root figure ; this product added to the divisor, will give the complete divisor. Multiply the complete divisor by the last root figure, subtract the product from the dividend, annex the next period to the remainder, and proceed as before until the whole root is extracted. If... | |
 | Pliny Earle Chase - 1844 - 258 pages
...found, by the last root figure ; this product added to the divisor, will give the complete divisor. Multiply the complete divisor by the last root figure, subtract the product from the dividend, annex the next period to the remainder, and proceed as before until the whole root is extracted. If... | |
 | Pliny Earle Chase - Arithmetic - 1848 - 244 pages
...found, by the last root figure ; this product added to the divisor, will give the complete divisor. Multiply the complete divisor by the last root figure, subtract the product from the dividend, annex the next period to the remainder, and proceed as before until the 'whole root is extracted. ,:.... | |
 | James Stewart Eaton - Arithmetic - 1857 - 376 pages
...the last root figure to the trial divisor, and the SUM will be the TRUE DIVISOR. 5. Multiply the true divisor by the last root figure, subtract the product from the dividend and to the remainder annex the next period for a new dividend. 6. Find a new trial divisor, and proceed as before until all the... | |
 | James Stewart Eaton - 1862 - 320 pages
...the last root figure to the trial divisor, and the SUM will be the TRUE DIVISOR. 5. Multiply the true divisor by the last root figure, subtract the product from the dividend, and to the remainder annex the next period for a new dividend. 6. Find a new trial divisor, and proceed as before, until all the... | |
 | James Stewart Eaton - Arithmetic - 1864 - 322 pages
...the last root figure to the trial divisor, and the SUM will be the TRUE DIVISOR. 5. Multiply the true divisor by the last root figure, subtract the product from the dividend, and to the remainder annex the next period for a new dividend. 6. Find a new trial divisor, and proceed as before, until all the... | |
 | William Frothingham Bradbury - Algebra - 1868 - 270 pages
...the last root figure to the trial divisor, and the SUM will be the TRUE DIVISOR. Multiply the true divisor by the last root figure, subtract the product from the dividend, and to the remainder annex the next period for a dividend. Find a new trial divisor, and proceed as before, until all (he periods... | |
 | William Frothingham Bradbury - Algebra - 1868 - 264 pages
...also at the right of the trial divisor for the TRUE DIVISOR. Multiply the true divisor by this new root figure, . subtract the product from the dividend, and to the remainder annex the next period, for a new dividend. NOTE 1. — When a root figure is 0, annex 0 also to the trial... | |
 | Robert Stewart (of Dundee.) - Arithmetic - 1871 - 248 pages
...quotient; the sum of these three numbers is the complete divisor, which multiply by the last quotient figure ; subtract the product from the dividend, and to the remainder annex the next period for a new dividend, to which find a divisor as before, and proceed in the same manner... | |
 | Henry Beadman Bryant, Emerson Elbridge White, Corydon Giles Stowell - Business mathematics - 1872 - 576 pages
...figure, and add the product to the trial divisor; the sum will be the true divisor. Multiply the true divisor by the last root figure, subtract the product from the dividend, and to the remainder annex the next period for a new dividend. 5. Add twice the root figure last found to the last term in column... | |
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Find the greatest cube in the left group and place its root at the right. Subtract the cube of this root from the left group, and to the remainder annex the next group for a dividend. III. Annex a cipher to the root already found and take three times... 
