 It will be seen that this third term is the square of the quotient obtained from dividing the second term by twice the square root of the first term.  Shorter Course in Algebra - Page 174by George Albert Wentworth - 1887 - 250 pagesFull view - About this book
 | William Frothingham Bradbury - Algebra - 1868 - 264 pages
...completed without multiplying the equation, by adding to both members the square of the quotient arising from dividing the second term by twice the square root of the first. This method also becomes the same as the first method when the coefficient of z2 is unity. NOTE 3.... | |
 | William Frothingham Bradbury - Algebra - 1877 - 302 pages
...completed without multiplying the equation, by adding to both members the square of the quotient arising from dividing the second term by twice the square root of the first. This method also becomes the same as the first method when the coefficient of 3? is unity. NOTE 3.... | |
 | George Albert Wentworth - Algebra - 1881 - 400 pages
...of the first term. 226. Every affected quadratic may be made to assume the form of air2 ± 2 abx = c. The first step in the solution of such an equation...of the quotient obtained from dividing the second tei'm by twice the square root of the first term. The second step is to extract the square root of... | |
 | George Albert Wentworth - Algebra - 1885 - 548 pages
...root ofthefirst term. 226. Every affected quadratic may be made to assume the form of а?a? ± 2 abx = c. The first step in the solution of such an equation...square ; that is, to add to each side the square of ihe quotient obtained from dividing the second term by twice the square root of the first term. The... | |
 | Webster Wells - 1885 - 368 pages
...the principle of Art. 261 ; that is, by adding to both members the square of the quotient obtained by dividing the second term by twice the square root of the first. 1. Solve the equation 9 ar — 5 ж = 4. The quotient of the second term divided by twice the 5 5 square... | |
 | Webster Wells - Algebra - 1885 - 382 pages
...the principle of Art. 261 ; that is, by adding to both members the square of the quotient obtained by dividing the second term by twice the square root of the first. 1. Solve the equation 9 яr — 5 ж = 4. The quotient of the second term divided by twice the 5 5... | |
 | Webster Wells - Algebra - 1885 - 370 pages
...the principle of Art. 261 ; that is, by adding to both members the square of the quotient obtained by dividing the second term by twice the square root of the first. 1. Solve the equation 9яr — 5ж= 4. The quotient of the second term divided by twice the square... | |
 | George Albert Wentworth - Algebra - 1888 - 518 pages
...lacks only the ¿Am¿ term, Js, of being a complete square. It will be seen that this third term is the square of the quotient obtained from dividing the second term by twice the square root of t he first term. 226. Every affected quadratic may be made to assume the form of aV i 2 abx = c. The... | |
 | George Albert Wentworth - Algebra - 1888 - 514 pages
...third term 62 of being a perfect square. This third term is the square of the quotient obtained by dividing the second term by twice the square root of the first term. Every affected quadratic may be made to assume the form aV ± 2abx = c (§ 131). To solve such an equation... | |
 | George Albert Wentworth - Algebra - 1891 - 380 pages
...quadratic may be made to assume the form of a2ar1 ± 2 abx = c. To solve such an equation : The first step is to complete the square; that is, to add to each...first term. The second step is to extract the square rdbt of each side of the resulting equation. The third and last step is to reduce the two resulting... | |
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