 A labourer dug two trenches, one of which was 6 yards longer than the other, for 17/. 16s., and the digging of each of them cost as many shillings per yard as there were yards in its length. What was the length of each ? Ans. 10, and 16 yards.  Elementary Algebra: For the Use of Schools - Page 190by William Smyth - 1851 - 236 pagesFull view - About this book
 | Miles Bland - Geometry - 1821 - 898 pages
...to the depth of the other. What are the depths ? Am. 5 feet, and 4 feet. yards in its side. Now had each of them cost as many shillings per yard as there were yards in the side of the other, I should have paid 17*. less. What was the size of each? Ans. One contained... | |
 | James Ryan - Algebra - 1824 - 550 pages
...the square of the other. Ans. lOv/5— 10, and 30— lOy/5. Prob. 23. A labourer dug two trenches, one of which was 6 yards longer than the other, for...17/. 16s., and the digging of each of them cost as man* shillings per yard as there were yards in its length. What was the length of each ? Ans. 10, and... | |
 | Miles Bland - Algebra - 1824 - 404 pages
...? Ans. 25, and 15 yards. 4. A person bought two pieces of linen, which together measured 36 yards. Each of them cost as many shillings per yard, as there were yards in the piece ; and their •whole prices were in the proportion of 4 to 1 . What Were the lengths of the... | |
 | James Ryan, Robert Adrain - Algebra - 1824 - 542 pages
...±24, and ±15. Prob. 17. A person bought two pieces of linen, which, together, measured 3G yards. Each of them cost as many shillings per yard, as there were yards in the piece ; and their whole prices were in the proportion of 4 to 1. What were the lengths of the pieces... | |
 | James Ryan - Algebra - 1826 - 430 pages
...10^/5. Prob. 23. A labourer dug two trenches, one of which was 6 yards longer than the other, for 111. 16s., and the digging of each of them cost as many...were yards in its length. What was the length of each t Ans. 10, and IC yards. Prob. 24. A company at a tavern had 8/. lus. to pay, but before the bill was... | |
 | Enoch Lewis - Algebra - 1826 - 180 pages
...2120; what are the sides? Ans. 26 and 38 feet. 4. A labourer dug two trenches, one of which was tí yards longer than the other, for £17 16s., and the digging of each cost as many shillings per yard, as there were yards in its length; what was the length of each? Ans.... | |
 | James Ryan, Robert Adrain - Algebra - 1835 - 388 pages
...the square of the other. Ans. 10 */ 5- 10, and 30— 10v/5. PROB. 23. A labourer dug two trenches, one of which was 6 yards longer than the other, for...What was the length of each ? Ans. 10, and 16 yards. PROB. 24. A company at a tavern had 8I. 15s. to pay, but before the bill was paid, two of them sneaked... | |
 | James Ryan - Algebra - 1838 - 412 pages
...the square of the other. Ans. 10v/5 — 10, and 30— 10-v/5. PROB. 23. A labourer dug two trenches, one of which was 6 yards longer than the other, for 17/. 16*., and the digging of each of them cost as many shillings per yard as there were yards in its length.... | |
 | John D. Williams - Algebra - 1840 - 634 pages
...£62 Is., for each of which I paid as many shillings per yard as there were yards in its side. Now had each of them cost as many shillings per yard as there were yards in a side of the other, I should have paid 17s. less. What was the size of each ? Let x and у be the... | |
 | George Roberts Perkins - Arithmetic - 1841 - 274 pages
...worked 48 — 18= 30 days. 6. A gentleman bought two pieces of silk, wbich together measured 38 yards. Each of them cost as many shillings per yard as there were yards in the piece, and their whole prices were as 4 to 1. What were the lengths of the pieces ? SOLUTION. Since... | |
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