| Timothy Walker - Geometry - 1829 - 138 pages
...For (108) • ' E H2=H G2 — E C& 110. — To make a parallelogram equivalent to a given s</i'(i,re, **and having the sum of its base and altitude equal to a given line — . Let** C (fig. 73) be the given square and A F73 B the given line. On AB as a diameter describe a semicircle.... | |
| Timothy Walker - Geometry - 1829 - 156 pages
...H. EH will be the side of the square required. For (108) K HI=H c*— EG*. 110. PROBLEM. — To make **a parallelogram equivalent to a given square, and having the sum of its base** F 73 and altitude equal to a given line. Let C (fig. 73) be the given square a nd AB the given line.... | |
| Benjamin Peirce - Geometry - 1837 - 216 pages
...and altitude. Demonstration. For AE -f- EB = AB, and by art. 290, AE X EB = DE2 = AC2. 298. Problem. **To construct a parallelogram, equivalent to a given square, and having the** difference of its base and altitude equal to a given line. • Solution. Upon the given line AB (fig.... | |
| Benjamin Peirce - Geometry - 1841 - 186 pages
...That is, by (5 280, the circle of which R is the radius is equal to the given polygon. 297. Problem. **To construct a parallelogram, equivalent to a given...sum of its base and altitude equal to a given line.** Solution. Upon the given line AB (fig. 138) as a diameter describe a semicircle. At A, erect the perpendicular... | |
| Benjamin Peirce - Geometry - 1847 - 204 pages
...EB are the required base and altitude. Proof. For AE + EB = AB, and by § 290, AE X EB 298. Problem. **To construct a parallelogram, equivalent to a given square, and having the** difference of its base and altitude equal to a given line. Solution. Upon the given line AB (fig. 139)... | |
| 1873 - 192 pages
...parallelogram of the same base and altitude. 7. To find a triangle equivalent to a given polygon. 8. **To construct a parallelogram equivalent to a given square, and having the** difference of its base and altitude equal to a given line. IX. 1. Prove that when oblique lines are... | |
| George Albert Wentworth - Geometry - 1877 - 416 pages
...triangle. B / А Ъ /l D с г T « \ ( i N I i \ TUI !- I M 7V" t /T \ PROPOSITION XXV. PROBLEM. 357. **To construct a parallelogram equivalent to a given...base and altitude of the required parallelogram be** epual to the given line M N. It is required to construct а О = R, and having the sum of its base... | |
| George Albert Wentworth - Geometry - 1877 - 426 pages
...equivalent to a given square, and having the sum of its base and altitude equal to a given line. ' if **R be the given square, and let the sum of the base...required parallelogram be equal to the given line** M N. lt is required to construct а О = R, and having the sum of its base and altitude = M N. Upon... | |
| George Albert Wentworth - Geometry - 1877 - 416 pages
...triangle, and then constructing a square equivalent to the triangle. PROPOSITION XXV. PROBLEM. 357. **To construct a parallelogram equivalent to a given...sum of its base and altitude equal to a given line.** РГ-&-- --4Q ¡I'— -¡N Let R be the given square, and let the sum of the base and altitude of the... | |
| George Albert Wentworth - Geometry - 1877 - 436 pages
...and altitude equal to a given line. S N ч у 'B Let R be the given square, and let the difference **of the base and altitude of the required parallelogram be equal to the given line** M N. It is required to construct а О = R, with the difference of the base and altitude = M N. Upon... | |
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