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" The area of a parallelogram is equal to the product of its base and altitude. "
Elements of Geometry and Trigonometry - Page 93
by Adrien Marie Legendre - 1852 - 432 pages
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The New Practical Builder and Workman's Companion, Containing a Full Display ...

Peter Nicholson - Architecture - 1823 - 210 pages
...rectangle is said to be contained by two of its sides, about any one of its angles. THEOREM 52. 147. The area of a parallelogram is equal to the product of its base and altitude. For the parallelogram ABCD is equal to the rectangle ABEF, which has the same base AB, and the same...
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Elements of Plane Geometry: For the Use of Schools

Nicholas Tillinghast - Geometry, Plane - 1844 - 108 pages
...parallelogram is equivalent to a rectangle which has an equal base and equal altitude. Cor. 2. Hence the area of a parallelogram is equal to the product of its base by its altitude (Prop. 1).* Cor. 3. Hence parallelograms of equal altitudes, are in proportion...
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Elements of Geometry and Conic Sections

Elias Loomis - Conic sections - 1849 - 252 pages
...the base, and the other the number of linear units contained in the altitude. PROPOSITION V. THEOREM. The area of a parallelogram is equal to the product of its base by its altitude. Cor. Parallelograms of the same base are to each other as their altitudes, and...
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Elementary Geometry: With Applications in Mensuration

Charles Davies - Geometry - 1850 - 238 pages
...EF+ AD x FB. THEOREM VIII. The area of any parallelogram is equal to the product of its Lose by its altitude. Let ABCD be any parallelogram, and BE its altitude : then will its area be equal to AB x BE. For, draw AF perpendicular to the base AB, and produce CD to F. Then, the parallelogram BD...
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Elementary Geometry: With Applications in Mensuration

Charles Davies - Geometry - 1850 - 218 pages
...ADxAB=ADxAE+-ADxEF+ADxFB. THEOREM VIII. The area of any parallelogram is equal to the product of its base by its altitude. Let ABCD be any parallelogram, and BE its altitude : then will its area be equal to AB X BE. For, draw AF perpendicular to the base AB, and produce CD to F. Then, the parallelogram BD...
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Elements of Geometry and Trigonometry: With Applications in Mensuration

Charles Davies - Geometry - 1886 - 340 pages
...EF+ AD x FB. THEOREM V1H. The area of any parallelogram is equal to the product of its base by its altitude. Let ABCD be any parallelogram, and BE its altitude : then will its area be equal to ABxBE. For, draw AF perpendicular to thn D base AB, and produce CD to F. Then, the parallelogram BD and the...
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Elements of Geometry and Trigonometry from the Works of A.M. Legendre ...

Charles Davies - Geometry - 1854 - 436 pages
...the square on a single one ; on a triple line it is nine times as great, &c. PROPOSITION V. THEOREM. The area of a parallelogram is equal to the product...and BE its altitude: then will its area be equal to AB x BE. Draw BE perpendicular to AB, and complete the rectangle ABEF. The parallelogram ABCD is equiv•...
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Mathematical Dictionary and Cyclopedia of Mathematical Science: Comprising ...

Charles Davies, William Guy Peck - Mathematics - 1855 - 628 pages
...is an equilateral parallelogram or rhojnbus. The diagonals of a rectangle are equal to each other. The area of a parallelogram is equal to the product of its base by its altitude. Any two parallelograms having the same or equal bases are to each other as their...
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Practical carpentry, joinery, and cabinet-making [by P. Nicholson. by P ...

Peter Nicholson - Cabinetwork - 1856 - 482 pages
...rectangle is said to be contained by two of its sides, about any one of its angles. THEOREM 43. 111. The area of a parallelogram is equal to the product of its base and altitude. For the parallelogram ABCD is equal to the rectangle ABEF, which has the same base AB, and the same...
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Elements of Geometry and Trigonometry from the Works of A. M. Legendre ...

Adrien Marie Legendre, Charles Davies - Geometry - 1857 - 442 pages
...as the square on a single one ; on a triple line it is nine times as great, PROPOSITION V. THEOREM. The area of a parallelogram is equal to the product of its boat and altitude. Let ABCD be any parallelogram, and BE its altitude: then will its area be equal...
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