 ... place not in the frigid zones,) to find what other day of the year is of the same length. RULE. Find the sun's place in the ecliptic for the given day, (by Problem XX.) bring it to the brass meridian, and observe the degree above it ; turn the globe...  A compendium of modern geography - Page 345by Alexander Stewart - 1850 - 443 pagesFull view - About this book
 | Thomas Keith - Astronomy - 1811 - 388 pages
...and observe the degree above it ; turn the globe on its axis till some other point of the ecliptic falls under the same degree of the meridian ; find...the ecliptic on the horizon, and directly against it you will find the day of the month required. This problem m»y be performed by the celestial globe... | |
 | John Lathrop - Astronomy - 1812 - 218 pages
...meridian, and observe the degree above it; turn the globe on its axis till some other point of the ecliptic falls under the same degree of the meridian ; find...the ecliptic on the horizon, and directly against it you will find the day of the month required. This Problem may be performed by the celestial globe in... | |
 | Thomas Keith - 1821 - 408 pages
...and observe the degree above it ; turn the globe on its axis till some other point of the ecliptic falls under the same degree of the meridian ; find...ecliptic on the horizon, and directly against it, you will find the day of the month required. This problem may be performed by the celestial globe in... | |
 | James M'Intire - Globes - 1826 - 234 pages
...globe round on its axis till some other point of the ecliptic comes under the same degree of the brass meridian; find this point of the ecliptic on the horizon, and directly against it you will find the day of the month required. Or, any two days of the year, which are the same number... | |
 | Joseph Guy - Astronomy - 1832 - 412 pages
...and observe the degree above it ; turn the globe on its axis till some other point of the ecliptic falls under the same degree of the meridian : find...the ecliptic on the horizon, and directly against it you will find the day of the month required. This Problem may be performed by the celestial globe in... | |
 | John Rorke - 1844 - 188 pages
...declination for the given day ; turn the globe till some other point of the ecliptic passes under that degree of the meridian ; find this point of the ecliptic on the horizon — the day required is opposite to it. Exercises. 1. What day is of the same length as the 1st of... | |
 | Joseph Guy - Astronomy - 1845 - 370 pages
...and observe the degree above it ; turn the globe on its axis till some other point of the ecliptic falls under the same degree of the meridian : find...the ecliptic on the horizon, and directly against it you will find the day of the month required. This Problem may be performed by Oie celestial globe in... | |
 | Thomas Keith - 1848 - 486 pages
...and observe the degree above it ; turn the globe on its axis till some other point of the ecliptic falls under the same degree of the meridian : find this point of the ecliptic on the horizon, and against it you will find the day of the month required. This Problem may be performed by the celestial... | |
 | James M'Intire - Astronomy - 1850 - 352 pages
...globe round on its axis till some other point of the ecliptic comes under the samedegree'of the brass meridian ; find this point of the ecliptic on the horizon, and directly against it you will find the day of the month required. Or, any two days of the year, which are the same number... | |
 | John White - 1882 - 330 pages
...the eeliptic for the given day to the brass meridian, and note the degree above it; turn the globe till some other point of the eeliptic falls under the same degree of the meridian; then find this point of the ecliptic on the horizon,—and directly opposite to it is the day of the... | |
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