| James Mitchell - Mathematics - 1823 - 666 pages
...root. 4. Subtract the cube of these two figures of the root from the first two periods on the left, and to the remainder annex the following period, for a new dividend, which divide as before ; and so on till the whole is finished. And finally point off as many figures... | |
| Samuel YOUNG (of Manchester.) - 1833 - 272 pages
...both in the root and on the right of the Disisor; also by it multiply the Divisor thus completed, and subtract the Product from the Dividend, and to the Remainder annex the next period for a new Dividend. To the completed Divisor add the figure last put in the root ; the... | |
| John Husband (math. master, Berwick.) - 1841 - 126 pages
...divisor and the root already found ; multiply the divisor thus completed by the figure of the root last found ; subtract the product from the dividend, and to the remainder annex the third period for a new dividend. Add the last figure of the root to the last divisor, the sum will... | |
| George Roberts Perkins - Arithmetic - 1841 - 274 pages
...the result will be the TRUE DIVISOR. Multiply the true divisor by this second figure of the root, and subtract the product from the dividend, and to the remainder annex the next period,for a SECCUD DIVIDEND. . ft IV. To the last TRUE DIVISOR, add the Jastfgure of the root,... | |
| Arithmetic - 1843 - 142 pages
...product write also the square of the trial-figure, then multiply the sum of these by the trial-figure, subtract the product from the dividend, and to the remainder annex the next period for a new dividend. EVOLUTION.ciphers for a new divisor, with which find anolner trialfigure,... | |
| George Roberts Perkins - Arithmetic - 1846 - 266 pages
...the result will be the TRUE DIVISOR. Multiply the true divisor by this second figurt of the root, and subtract the product from the dividend, and to the remainder annex the next period, for a SECOND DIVIDEND. IV. To the last TRUE DIVISOR, add the last figure of the not, for... | |
| George Roberts Perkins - Arithmetic - 1849 - 346 pages
...the result will be the TRUE DIVISOR. Multiply the true divisor by this last figure of the root, and subtract the product from the dividend, and to the remainder annex the next period, for a NEW DIVIDEND. IV. To the last TRUE DIVISOR add the last figure of the root ; the... | |
| George Roberts Perkins - Arithmetic - 1849 - 356 pages
...the result will be the TRUE DIVISOR. Multiply the true divisor by this second figure of the root, and subtract the product from the dividend, and to the remainder annex the next period for a SECOND DIVIDEND. IV. To the last TRUE DIVISOR add the last figure of the root for... | |
| Rufus Putnam - Arithmetic - 1849 - 402 pages
...down the next period for a dividend . 4 . Multiply the complete divisor by the last figure m the root, subtract the product from the dividend, and to the remainder annex the next period for a new dividend. If the product should exceed the dividend, diminish the last figure... | |
| George Roberts Perkins - Arithmetic - 1850 - 364 pages
...the result will be the TRUE DIVISOR. Multiply the true divisor by this last figure of the root, and subtract the product from the dividend, and to the remainder annex the next period, for a NEW DIVIDEND. 1 V. To the last TRUE DIVISOR add the last figure of the root ; the... | |
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