 | Samuel Earnshaw - Statics - 1845 - 290 pages
...moment of a force about If the direction of the force be perpendicular to the given line, the moment is equal to the product of the force into the length of a line which is perpendicular both to the force and the line about which the moment is required. If... | |
 | William Holms Chambers Bartlett - Mechanics - 1850 - 662 pages
...SOLIDS. which shows that the quantity of work of a force, not immediately opposed to a resistance, is equal to the product of the force into the length of path described by its point of application, estimated in the direction of the farce. Fig. 42. Quantity... | |
 | William Holms Chambers Bartlett - Astronomy - 1850 - 640 pages
...SOLIDS. which shows that the quantity of work of a force, not immediately opposed to a resistance, is equal to the product of the force into the length of path described l>y its point of application, estimated in the direction of the force. Fig. 42. Quantity... | |
 | William Holms Chambers Bartlett - Astronomy - 1855 - 646 pages
...SOLIDS. which shows that the quantity of work of a force, not immediately opposed to a resistance, is equal to the product of the force into the length of path described by its point of application, estimated in the direction of the force. Fig. 42. Quantity... | |
 | Industrial arts - 1878 - 714 pages
...BYMEA. [25477.] — More Terms. — " Bromo-Iodine " makes a mistake in his definition of v.'o/fc. The work done by a force is equal to the product of the force into the space it moves through, so that in the case of a falling body it is the product of its iceight into... | |
 | Andrew Jamieson - Mechanical engineering - 1895 - 448 pages
...of the effort, we get : — Work done = component of W parallel to AB x displacement, AB. „ „ = W sin ax A B. „ „ = W x AB sin a. „ = W x B...the force. EXAMPLE II. — A body is dragged along a floor by means of a cord which makes a constant angle of 30° with the floor. The tension in the cord... | |
 | Andrew Jamieson - Mechanical engineering - 1895 - 446 pages
...— Work done = com ponent of W parallel to AB x displacement, AB. „ „ = W sin ax A B. i> „ = W x AB sin a. „ = W x B C. Here, again, BC is the...the force. EXAMPLE II. — A body is dragged along a flo;:r by means of a cord which makes a constant angle of 30° with the floor. The tension in the cord... | |
 | Andrew Jamieson - Mechanical engineering - 1896 - 498 pages
...displacement, AB. » » = W sin ax А В. ,, ,, = Л\г x AB ein, a. „ = W x В С. Here, again, В С is the length of the projection of AB on the direction...the force. EXAMPLE II. — A body is dragged along a flo'.r by means of a cord which makes a constant angle of 30° with the floor. The tension in the cord... | |
 | Ellis H. Crapper - Electric measurements - 1897 - 168 pages
...to produce rotation about a point is termed (he " moment of the force" and numerically the moment of a force is equal to the product of the force into the perpendicular distance from the point. That is, Moment of a force = F x perpendicular distance, = H... | |
 | Andrew Jamieson - Mechanical engineering - 1898 - 586 pages
...the effort, we get : — Work done = component of W parallel to AB x displacement, AB. „ „ = VV sin ax A B. ,, „ = W x AB sin a. „ - W x B C....the force. EXAMPLE II. — A body is dragged along a flot r by means of a cord which makes a constant angle of 30° with the floor. The tensi m in the cord... | |
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= W x B C. Here, again, BC is the length of the projection of AB on the direction or line of action of the resistance, W. Hence, we have the following statement, which is often useful : — The work done by a force is equal to the product of the force... 
