First Part of an Elementary Treatise on Spherical Trigonometry |
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Solution of Spherical Oblique Triangles , when two sides and the included angle are known ( 615-620 ) , or ( 844 ) ... on the equality of triangles ( 861 ) , ( 863 ) , Sines , & c . of angles greater than 180 ° ( 705 ) , CHAPTER IV .
Solution of Spherical Oblique Triangles , when two sides and the included angle are known ( 615-620 ) , or ( 844 ) ... on the equality of triangles ( 861 ) , ( 863 ) , Sines , & c . of angles greater than 180 ° ( 705 ) , CHAPTER IV .
Page 1
In the present treatise those spherical triangles only are treated of , in which the sides and angles are less than 180 ° . 2. The angle , formed by two sides of a spherical triangle , is the same as the angle formed by their planes .
In the present treatise those spherical triangles only are treated of , in which the sides and angles are less than 180 ° . 2. The angle , formed by two sides of a spherical triangle , is the same as the angle formed by their planes .
Page 2
To investigate some relations between the sides and angles of a spherical right triangle . Solution . The importance of this problem is obvious ... The angle of the planes BOC and AOC is equal to the 2 SPHERICAL TRIGONOMETRY .
To investigate some relations between the sides and angles of a spherical right triangle . Solution . The importance of this problem is obvious ... The angle of the planes BOC and AOC is equal to the 2 SPHERICAL TRIGONOMETRY .
Page 4
From triangle A'B'C ' we have by ( 5 ) ( 437 ) and ( 428 ) , and the fact that the angle B'A'C ' is equal to the ... Corresponding to the preceding equation between the hypothenuse h , the angle A , and the adjacent side b , there must ...
From triangle A'B'C ' we have by ( 5 ) ( 437 ) and ( 428 ) , and the fact that the angle B'A'C ' is equal to the ... Corresponding to the preceding equation between the hypothenuse h , the angle A , and the adjacent side b , there must ...
Page 7
A = tang . b cotan . h ; ( 469 ) Hence , from the equality of the second members of ( 468 ) and ( 469 ) , cos . A cos . a sin . B. Tenthly . The preceding equation between the side a , the opposite angle A , and the adjacent angle B ...
A = tang . b cotan . h ; ( 469 ) Hence , from the equality of the second members of ( 468 ) and ( 469 ) , cos . A cos . a sin . B. Tenthly . The preceding equation between the side a , the opposite angle A , and the adjacent angle B ...
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First Part of an Elementary Treatise on Spherical Trigonometry (Classic Reprint) Benjamin Peirce No preview available - 2017 |
First Part of an Elementary Treatise on Spherical Trigonometry Benjamin Peirce No preview available - 2016 |
Common terms and phrases
A'BC acute adjacent angles angle are known becomes calculated called CHAPTER Corollary corresponding cosec cotan deduced Demonstration determined differs divided equal to 90 equation EXAMPLES factor fractions given angle gives greater than 90 half the sum hemisphere Hence hypothenuse impossible included angle legs Lemma less than 90 Let ABC fig let fall logarithm lunary surface measured middle Napier's Rules negative numerator obtained obtuse opposite angle opposite side perpendicular perpendicular BP positive Problem proportion proved quantity quotient reduce result right angle satisfy Scholium second member Secondly sides and angles sides equal signs sine Solution Solution of Spherical solve a spherical solve the triangle spherical right triangle spherical triangle ABC substituted supplements surface ABC tang tangent of half Theorem Thirdly tive trian triangle ABC figs whence
Popular passages
Page 1 - A spherical triangle is a portion of the surface of a sphere, bounded by three arcs of great circles.
Page 69 - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. D c A' D' Hyp. In triangles ABC and A'B'C', ZA = ZA'. To prove AABC = ABxAC. A A'B'C' A'B'xA'C' Proof. Draw the altitudes BD and B'D'.
Page 69 - THEOREM. The surface of a spherical triangle is measured by the excess of the sum of its three angles above two right angles, multiplied by the tri-rectangular triangle.
Page 8 - I. The sine of the middle part is equal to the product of the tangents of the adjacent parts.
Page 8 - II. The sine of the middle part is equal to the product of the cosines of the opposite parts.
Page 30 - Any angle is greater than the difference between 180° and the sum of the other two angles.
Page 63 - The cosine of half the sum of two sides of a spherical triangle is to the cosine of half their difference as the cotangent of half the included angle is to the tangent of half the sum of the other two angles. The sine of half the sum of two sides of a spherical...
Page 62 - The sine of half the sum of two sides of a spherical triangle is to the sine of half their difference as the cotangent of half the included angle is to the tangent of half the difference of the other two angles.
Page 71 - ... and the sum of the angles in all the triangles is evidently the same as that of all the angles of the polygon ; hence, the surface of the polygon is equal to the sum of all its angles, diminished by twice as many right angles as it has sides less two, into the tri-rectangular triangle.